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3 years ago

I don't remember how to do this. Please help

Mathematics

2 answers:

Karolina [17]3 years ago

6 0

Ok so let’s say that the first number is is the c axis. and the number is -6 you would play that one negative -6 in the 3rd quadrant

Eva8 [605]3 years ago

4 0

Answer:

Look on khan academy it has the answers

Step-by-step explanation:

hope you find your answer

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What does 7/18 + 2/27=

victus00 [196]

The answer would be 25/54

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4 years ago

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An angle is drawn in standard position passing through the unit circle at (0.643,0.766). The angle in standard position θ has a

Flura [38]

<h2>Hello!</h2>

The asnwer is: Cos50° ≈ 0.643

A unit circle is a cirgle with a radius equal of 1, knowing that, also know the following:

The angle is drawn passing trough the unit circle at (0.643,0.766) it means that:

$x=0.643\\y=0.766$

So,

Cos50° ≈ 0.643

We can prove that by following the next steps:

- If it's a unit circle,here is a right triangle with hypotenuse of 1,

$1^{2}=x^{2}+y^{2}$

$1^{2}=0.643^{2}+0.766^{2}$

$1^{2}=0.4134 +0.5867$

$1=1.0001=1$

- We can determine the cosine of the angle by the following formula:

$cos(\alpha)=\frac{x}{hypotenuse} \\cos(\alpha)^{-1}=cos(\frac{0.643}{1})^{-1} \\\alpha=49.98$

Therefore,

Cos(α)=49.98°≈50°

Also, if there is a right triangle, according to the Pythagorean Thorem:

$1^{2}=(Cos(\alpha))^{2}+(Sin(\alpha))^{2} \\Cos(50)=\sqrt{1-(Sin(50))^{2}}=0.6427$

Hence,

Cos50° ≈ 0.643

Have a nice day!

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3 years ago

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A couple is sitting inside a marriage hall, in a row that can accommodate a maximum of six couples. On the right of this couple

NeX [460]

There are 5 couples are sitting in the row

<h3>How many couples are sitting in the row?.</h3>

The given parameters are

Maximum = 6 couples

In the hall, we have the following arrangements

<u>First couple</u>

Right = 2 couples

Left = 1 couple

<u>Another couple</u>

Left = 3 couple

Right = 1 couples

The left of the other couple is the right of the first couple

So, we have the following arrangements:

<u>First couple (1)</u>

Right = 2 couples

Left = 1 couple

<u>Another couple</u>

Right = 1 couples

The total number of couples is

Total = 1 + 2 + 1 + 1

Evaluate the sum

Total = 5

Hence, there are 5 couples are sitting in the row