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joja [24]
3 years ago
5

What is the approximate area of the shaded sector in the circle shown below?

Mathematics
1 answer:
stich3 [128]3 years ago
4 0

Answer: 26.5cm2

Step-by-step explanation:

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B.$120

Step-by-step explanation:

find 8 on the bottom, and go up until you find the dot. then look to the left to see what number matches it on the left side.

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What are the domain and range of h(x) = 3|x|? A. domain: all real numbers; range: y ≤ 0 B. domain: x ≥ 0; range: all real number
frozen [14]

Answer:

D

Step-by-step explanation:

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2 years ago
Colin surveyed 12 teachers at school to determine how much each person budgets for lunch. He records his results in the table. W
zmey [24]

Answer:

<em>As mean and median are equal, so the data will be in normal distribution in shape of a symmetrical "bell curve".</em>

Step-by-step explanation:

The given data:   10   5   8   10   12   6   8   10   15   6   12   18

<u>Mean is the simple average of all data</u>. As, there are total 12 data, so the Mean will be:  \frac{10+5+8+10+12+6+8+10+15+6+12+18}{12}= \frac{120}{12}=10

For finding the Median, <u>first we need to rearrange the data according to the numerical order and then identify the middle value</u>. So........

5   6   6   8   8   10   10   10   12   12   15   18

Here the middle values are 10 and 10. So, the median will be the average of those two middle values.

Thus, Median =\frac{10+10}{2}=\frac{20}{2}=10

We can see that, <u>the relationship between the mean and the median is "they are equal"</u>. So, the data will be in normal distribution and the shape will be symmetrical "bell curve".

8 0
2 years ago
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You have 12 shirts and plan to wear a different one each day from Monday
JulsSmile [24]
It should be 95,040. On the first day, you have 12 choices. On the second, eleven, and so on, until day 5. 12x11x10x9x8.
6 0
3 years ago
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A(4,-7) B(-2,1) find AB
Natali5045456 [20]

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\A(\stackrel{x_1}{4}~,~\stackrel{y_1}{-7})\qquadB(\stackrel{x_2}{-2}~,~\stackrel{y_2}{1})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\AB=\sqrt{[-2-4]^2+[1-(-7)]^2}\implies AB=\sqrt{(-2-4)^2+(1+7)^2}\\\\\\AB=\sqrt{(-6)^2+8^2}\implies AB=\sqrt{36+64}\implies AB=\sqrt{100}\implies AB=10

8 0
3 years ago
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