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morpeh [17]
2 years ago
15

The histogram to the right represents the weights​ (in pounds) of members of a certain​ high-school programming team. What is th

e class​ width? What are the approximate lower and upper class limits of the first​ class? 100 120 140 160 180 200 220 240 0 1 2 3 4 5 6 Weight (lbs) Frequency A histogram with horizontal axis labeled "Weight (pounds)" from 100 to 240 in intervals of 20 and vertical axis labeled "Frequency" from 0 to 6 in intervals of 1 contains seven adjacent vertical bars with heights as follows: 100 to 120, 4; 120 to 140, 1; 140 to 160, 1; 160 to 180, 3; 180 to 200, 3; 200 to 220, 4; 220 to 240, 2. What is the class​ width? The class width is nothing. ​(Simplify your​ answer.) What are the approximate lower and upper class limits of the first​ class? The approximate lower class limit is nothing. The approximate upper class limit is nothing. ​(Simplify your​ answers.)
Mathematics
1 answer:
AVprozaik [17]2 years ago
4 0

Answer:

Class width=20

Lower class limit of first class=100

Upper class limit of first class=120

Step-by-step explanation:

The class width can be calculated by taking the difference of two consecutive upper class limits or lower class limits.

Now we take any two consecutive upper class limits or lower class limits from classes 100-120,120-140,140-160,160-180,180-200,200-220,220-240.

We take upper class limits of first and second class i.e. 100 and 120.

Class width=120-100=20

Class width=20

The approximate lower and upper class limits of the first class from classes  100-120,120-140,140-160,160-180,180-200,200-220,220-240 are 100 and 120.

Class limits for first class is 100-120.

Lower class limit of first class=100

Upper class limit of first class=120

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lbvjy [14]

Answer:

2.38 lb bag = 4.99/lb   5.08 lb bag = 5.21/lb  The 2.38 is the better buy

Step-by-step explanation:

11.88/2.38 = 4.99

26.47/5.08 = 5.21

4.99 is cheaper than 5.21 so the 2.38 lb bag is better buy

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2 years ago
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6 0
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A company rents water tanks shaped like cylinders. Each tank has a radius of 3 feet and a height of 2 feet. The cost is $4 per c
vivado [14]

Answer:

Cost to rent one tank=226.08 Dollars

Step-by-step explanation:

Radius of the cylindrical tank=3 feet

Height of the tank= 2 feet

Cost to rent one tank= Volume of one tank * cost to rent one cubic feet of volume

Volume of the cylindrical tank:

                                         =\pi r^2

As,  \pi =\frac{22}{7}=3.14

Putting the values in the formula:

Volume of the tank:

                                    =3.14*(3*3)*2\\\\=3.14*9*2\\\\=3.14*18\\\\=56.52feet^3

Cost to rent one cubic feet= 4 Dollars

Cost to rent 56.52 Cubic feet of one tank;

   = 4*56.52

=226.08 Dollars

5 0
3 years ago
A+ B = 30. A:B what is equivalent to 2:3
Paraphin [41]
2/3 and 12/18 are equivalent fractions, and 12+18 = 30 so the answer is 12:18 
5 0
3 years ago
15x-7=2+12x I need help with this
Amanda [17]

Answer:

\huge{ \boxed{ \bold{ \tt{x = 3}}}}

<h3>♁ Question : Solve for x</h3>
  • 15x - 7 = 2 + 12x

<h3>♁ Step - by - step explanation</h3>
  • \text{15x - 7 = 2 + 12x}

Move 12x to L.H.S ( Left Hand Side ) and change it's sign

➛\sf{15x - 12x - 7 = 2}

Move 7 to R.H.S ( Right Hand Side) and change it's sign

➛\sf{15x - 12x = 2 + 7}

Subtract 12x from 15x

Remember that only coefficients of like terms can be added or subtracted.

➛\sf{3x = 2 + 7}

Add the numbers : 2 and 7

➛\sf{3x = 9}

Divide both sides by 3

➛ \sf{ \frac{3x}{3}  =  \frac{9}{3}}

➛ \boxed{ \bold{ \sf{x = 3}}}

The value of x is \boxed{ \sf{3}}

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

☄ Now, let's check whether the value of x is 3 or not!

<h3>☥ Verification :</h3>

\sf{15x - 7 = 2 + 12x}

\dashrightarrow{ \sf{15 \times 3 - 7 = 2 + 12 \times 3}}

\dashrightarrow{ \sf{45 - 7 = 2 + 36}}

\dashrightarrow{ \sf{38 = 38}}

L.H.S = R.H.S ( Hence , the value of x is 3 ).

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

<h3>✒ Rules for solving an equation :</h3>
  • If an equation contains fractions ,multiply each term by the L.C.M of denominators.
  • Remove the brackets , if any.
  • Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their sign ' + ' into ' - ' and ' - ' into ' + ' .
  • Simplify and get the single term on each side.
  • Divide each side by the coefficient of variable and then get the value of variable.

Hope I helped!

Have a wonderful time ! ツ

~TheAnimeGirl

5 0
2 years ago
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