Hack
for y=ax^2+bx+c
the xvalue of the vertex is -b/2a
and the y value is found by subsituting that for x
so
-b/2a
h(t)=2x^2+4x+7
a=2
b=4
-b/2a=-4/(2*2)=-4/4=-1
the y value
h(-1)=2(-1)^2+4(-1)+7
h(-1)=2(1)-4+7
h(1)=2+3
h(1)=5
(-1,5) is da vertex
Answer:
b ≥ 500
Step-by-step explanation:
since the balance has to be at least 500, b has to be grater than or equal to 500, so b ≥ 500
Solutions just means the amount of times the lines intersect, so there are no solutions. Since the lines are parallel, they’re going the exact same direction forever and ever, never intersecting. Hope this helps!
Calculate and multiply to get
-4/(-6)+7 - 2x(-2)/-1x3+7
Next remove parentheses and calculate,
You'll get -4/-6+7 - 2x(-2)/4
Then calculate and reduce,
-4/1 - -2/2
Reduce and divide to get -4-(-1)
Remove parentheses, -4+1
And calculate to get your final answer
= -3
