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3 years ago

What are the three ways to represent a ratio??

1 answer:

4 0

You can write it as a fraction . . . . . 5/4

You can write it as a decimal . . . . . 1.25

Or you can write it as a ratio . . . . . 5 : 4

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Express 73 kilometers per hour in miles per hour

lorasvet [3.4K]

45.36km/hr.............. ...........

5 0

3 years ago

I WILL MARK BRAINLIEST IN 5 MINUTES! solve this and explain

miskamm [114]

Answer:

no, it's not.

Step-by-step explanation:

300- 284 = 16

284 - 236 = 48

236 - 156 = 80

156 - 44 = 112

for every one the top line goes up, the bottom line changes too, but it's not at a constant rate. it's not constant, therefore it cannot be linear.

the rate of change formula (or slope formula, they're the same thing) is :

y2- y1/ x2 -x1 and to solve it you plug in the points. x is the same a t and y is h

284-300/ 1-0

-16 /1

-16 (this is the rate of change between the first two points)

236- 284/ 2-1

-48/ 1

-48 (rate of change between the second and third points)

since the rate of change isn't constant, it's not possible for it to be a linear relationship.

7 0

3 years ago

there are 3 teams of 18 employees working today company policy says that we need to have one supervisor for every 8 employees on

Vadim26 [7]

The answer is 6.75. Since if you divide the number by 8 you get 6.75.

8 0

2 years ago

Read 2 more answers

(t-2)(t+1)(t+1) what is this when foiled out

mario62 [17]

(t-2)(t+1)(t+1)
t^2+t-2t-2(t+1)
t^2-t-2(t+1)
t^3-t^2-2t+t^2-t-2
t^3+-3t-2

3 0

2 years ago

Read 2 more answers

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0

1 year ago