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Katyanochek1 [597]
2 years ago
9

A distribution is given as X ~ U(0, 12). Find P(x > 6). (Enter an exact number as an integer, fraction, or decimal.)

Mathematics
1 answer:
astra-53 [7]2 years ago
6 0

Answer:

Step-by-step explanation:

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5. Landon bought a new car for $16,000 and it depreciates 4.5% every year. Write a function that describes
snow_tiger [21]

Answer:

<h3>The value C(t) of the car after  5  years is $12709.</h3>

Step-by-step explanation:

Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.

<h3>To find the value C(t) of the car after  5  years:</h3>

Initial value C(0)= $16,000

Depreciation rate is  r=\frac{4.5}{100}

<h3>∴ r=0.045</h3>

Period ,  t=5 years

C(t)=C(0)(1-r)^t

Substitute the values we get

C(5)=16000(1-0.045)^5

=16000(0.955)^5

=16000(0.7943)

∴ C(5)=12708.8

<h3>The value C(t) of the car after  5  years is  $ 12709</h3>
3 0
2 years ago
Which expression is equivalent to -18a^-2b^5/-12a^-4b^-6
crimeas [40]

Answer:

  c.  3a^2b^11/2

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)/(a^c) = a^(b-c)

__

 \dfrac{-18a^{-2}b^5}{-12a^{-4}b^{-6}}=\dfrac{-18}{-12}a^{-2-(-4)}b^{5-(-6)}=\boxed{\dfrac{3a^2b^{11}}{2}}

3 0
2 years ago
The explicit rule for a sequence is given. an=4n−1 What is the recursive rule for the sequence?
Gnom [1K]

Answer:

a_{n+1}=a_n+4

Step-by-step explanation:

Have in mind the definition of the term a_n=4\,n-1, and now work on what the term a_{n+1} is based on the previous definition:

a_{n+1} = 4\,(n+1)-1\\a_{n+1}=4\,n+4-1

In the next step do NOT combine the numerical values, but try to identify the a_n term (4\,n-1) in the expression (notice the use of square brackets to group the relevant terms):

a_{n+1}=4\,n+4-1\\a_{n+1}=[4\,n-1]+4\\a_{n+1}=a_n+4

So now we have the term "a_{n+1}" defined in a recursive manner based on the previous term "a_n"

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2 years ago
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