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nordsb [41]
2 years ago
9

Calculate the price with VAT of the following case.

Mathematics
1 answer:
AlekseyPX2 years ago
8 0

Answer: $427140

Step-by-step explanation:

Firstly, we'll add MP to the profit and this will be:

= Rs 400000 + Rs 20000

= Rs 420000

Since there is a discount of 10%, this will then be:

= 420000 - (10% × 420000)

= 420000 - 42000

= $378000

With a VAT of 13%, then the final price will be:

= $378000 + (13% × $378000)

= $378000 + (0.13 × $378000)

= $378000 + $49140

= $427140

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jok3333 [9.3K]

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Step-by-step explanation:

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3 0
3 years ago
Find sin θ if θ is in Quadrant III and tan θ = . 0.958
Leokris [45]
Use the following identities:
sec^2 = 1  + tan^2 \\  \\ sec = \frac{1}{cos} \\  \\ sin^2 = 1 - cos^2
Also because the angle is in quadrant 3, sin must be negative.
Therefore
sin = - \sqrt{1 - \frac{1}{1 + tan^2}}
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7 0
2 years ago
How do you do this question?
quester [9]

Step-by-step explanation:

F(x) = ∫ₐˣ t⁷ dt

F(x) is the area under f(t) between t=a and t=x.  When x=a, the width of the interval is 0, so the area is zero.

F(6) = 0, so a = 6.

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F(6) = 0

3 0
3 years ago
What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as
Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

P(C | J) = 0.15 / (0.25)

P(C | J) = 0.6 = 0.60

5 0
2 years ago
Which of the following values are in the range of the function graphed below?
Dafna1 [17]

Answer:

A. 1

Step-by-step explanation:

I see only one red function line in the graph. this line represents the simple function y = 1, for x in the interval [-2,1].

the domain of a function defines the possible values for x, and the range of a function defined the possible values for y.

this function has only one possible value for y : 1

so, only A applies.

5 0
3 years ago
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