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3 years ago

28 -4t = 3t is it 4 the answer

Mathematics

2 answers:

Julli [10]3 years ago

7 0

Answer: yes good job

antiseptic1488 [7]3 years ago

4 0

Answer:

Yes!

Step-by-step explanation:

28 - 4t = 3t

Isolate t:

28 = 7t

t = 28 / 7 = 4

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14. Two cars are traveling on two different roads that are perpendicular to each other. On a coordinate

Klio2033 [76]

Answer:

-68/7

Step-by-step explanation:

slope1 of Car 1 that pass (-5,-8) (2,7)

= (y1-y2)/(x1-x2)=(2-(-5))/(7-(-8))=7/15

Slope2 of car 2 that pass (5,1) (10,y)

slope 1 and slope2 are perpendicular =>slope 2 =-15/7

make slope2 y=(-15/7)x+b

for it pass(5,1) => 1=(-15/7)5+b =>b=82/7 => y=(-15/7)x+82/7

put (10,y) in => y=(-15/7) 10+82/7=-68/7

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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Vadim26 [7]

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Step-by-step explanation:

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3 years ago

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Naily [24]

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3 years ago

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Please help me with this problem <br> Evaluate (-½·3)³

-Dominant- [34]

Answer: -27/8

Step-by-step explanation:

$\left(-\frac{1}{2}\cdot \:3\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\quad \mathrm{if\:}n\mathrm{\:is\:odd}$

$\left(-\frac{1}{2}\cdot \:3\right)^3=-\left(\frac{1}{2}\cdot \:3\right)^3$

$=-\left(\frac{1}{2}\cdot \:3\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n$

$\left(\frac{1}{2}\cdot \:3\right)^3=\left(\frac{1}{2}\right)^3\cdot \:3^3$

$=-\left(\frac{1}{2}\right)^3\cdot \:3^3$

$=-\frac{1}{8}\cdot \:3^3$

$=-\frac{1}{8}\cdot \:27$

$=-\frac{27}{8}$

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2 years ago