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Gemiola [76]
2 years ago
12

18+17+16+15+14+13+12+11+10 what is the answer​

Mathematics
1 answer:
telo118 [61]2 years ago
4 0
Answer to the math question is:
126
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Which number has a value between -8.423 and -8.395?
pav-90 [236]

Answer:

Step-by-step explanation:

Jmeu eimejrimr

5 0
3 years ago
Members of the swim team want to wash their hair. The bathroom has less than 5600 liters of water and at most 2.5 liters of sham
nordsb [41]

Answer:

Yes, the bathroom has enough water and shampoo for all of them.

Step-by-step explanation:

70L+ 60S < 5600

Putting 8 into L and 7 into S, gives:

70(8) + 60(7) = 560 + 420 = 980

That is definitely less than 5600, so water is OK.

Now,

0.02L + 0.01S

Putting 8 into L and 7 into S, gives:

0.02(8) + 0.01(7) = 0.16 + 0.07 = 0.23

That's definitely less than 2.5 liters, so shampoo is OK as well.

Hence, bathroom has enough water and shampoo for them.

7 0
3 years ago
Read 2 more answers
Which line segment is drawn in the figure?<br><br> A.YZ<br> B.WY<br> C.XZ<br> D.WZ
Dima020 [189]
The line segment shown in the figure is C. XZ. A line segment is a line that is bounded by 2 endpoints, hence the line is not infinite. As shown in the figure, only points X and Z are visibly connected. There are no visible lines connecting the other points together.
6 0
3 years ago
Read 2 more answers
25 points!!!!!!!!
podryga [215]

Answer:

A is your answer, my guy

Step-by-step explanation:

4x1=4

3x-1=-3

5x1=5

4+(-3)+5=6

6x1=6

8x-1=-8

6x1=6

6+(-8)+6=4

4x1=4

2x-1=-2

6x1=6

4+(-2)+6=8

8 0
3 years ago
A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h
creativ13 [48]

It is given in the question that

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by

V = x^2h cm^3

And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.

Here we differentiate V with respect to t, and we use product rule, that is

V = 2xh(dx/dt)+ x^2(dh/dt)

Substituting the given values , we will get

[tex]dV/dt = 2(12)(6)(-2)+ 12^2(1)[/tex]

dV/dt = -288+144 = -144cm^3/min

So at that moment, the volume is decreasing at the rate of

144 cm^3/min

4 0
3 years ago
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