Question

A body is projected from aa point such that the horizontal and vertical components of its velocity are n.net/?f=640ms%5E-%5E1" id="TexFormula1" title="640ms^-^1" alt="640ms^-^1" align="absmiddle" class="latex-formula"> and $480 ms^-^1$ respectively . (Take g = $10ms^-^1$ )
i. Calculate the greatest height attained above the point of projection
A.600m B.1215 m C.1521 m D. 11520m E. 20480m

Answer 1

D. 11520m

Answer:

Solution given:

initial velocity[u]=480m/s

g=10m/s²

maximum height=?

now

we have

maximum height=$\frac{u²sin²\theta}{2g}$

where

$\theta=90°$

=$\frac{480²*sin90}{2*10}=11520m$