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olga_2 [115]
3 years ago
10

Write out the first four terms of the maclaurin series of f(x) if f(0)=7,f′(0)=3,f′′(0)=13,f′′′(0)=12

Mathematics
1 answer:
Alexxx [7]3 years ago
6 0
The general from for a maclaurin series is the nth derivative times x to the nth power divided by n factorial:
\frac{f(0)}{0!}x^{0}+ \frac{f'(0)}{1!}x^{1}+ \frac{f''(0)}{2!}x^{2}+ \frac{f'''(0)}{3!}x^{3}  \\ \\
7+ 3x+ \frac{13}{2}x^{2}+ 2x^{3}

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<u>Given</u>:

Given that the radius of the figure is 6 units.

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<u>Angle of the shape:</u>

The angle of the shape is given by

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<u>Area of the shape:</u>

The area of the shape can be determined using the formula,

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Step-by-step explanation:

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hichkok12 [17]

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Find all values of a such that (a-3)/sqrta=-sqrta
Mariana [72]

Answer:

From the Pythagorean theorem...

 

[ distance between (a, 7)  and  (2, 1) ]2   =   [a - 2]2  +  [7 - 1]2

 

And they tell us that the distance equals  3√5  , so

 

[  3√5 ]2   =   [a - 2]2  +  [7 - 1]2

 

45   =   [a - 2]2  +  36

 

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±√9  =   a - 2

 

± 3   =   a - 2

 

± 3  +  2   =   a

 

a  =  3 + 2  =  5          or          a = -3 + 2  =  -1

 

and

 

5  +  -1   =   4

Step-by-step explanation:

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andreev551 [17]
Since the 9 is greater than or equal to 5, we'll round our number up by adding 1 to the 3 in the hundreds place, making it a 4. And also by changing all digits to the right of this new 4 into zeros.

And our rounded number would be 400

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