Answer:
False
Explanation:
IPv4 address are composed of four octets (8 bit numbers), ranging from <em>0.0.0.0 to 255.255.255.255</em>
All those 32 bits, in decimal notation, can form a total of
different addresses.
Being more than 4 billion addresses and ignoring that some addressesare reserved for special uses, even present human population almost doubles that number.
So it is safe to state that IPv4 addresses is <u>not </u>enough to give every blade of grass its own IP.
<h2>
Answer:</h2>
i. Number of parameters
ii. Type of parameters
<h2>
Explanation:</h2>
When there are two or more constructors, definitely with the same name, in a given class, then the constructors are said to be overloaded. An overloaded constructor appears declared many times in a class but each time with different number of parameters and/or type of parameters.
For example, given a class Test, the following combination of constructors can exist;
i. public Test(int x){
}
ii. public Test(String m){
}
iii. public Test(int a, String b){
}
<em>The following should be noted;</em>
In the case of combination (i) and (ii), the constructors have the same number of parameters but different type of parameter. In other words, they both have 1 parameter but while the first one has a parameter type of <em>int</em>, the second has a parameter type of <em>String</em>.
In the case of combination (ii) and (iii), the constructors have different number of parameters and of course different type of parameters. In other words, the second constructor has 1 parameter of type <em>String</em> while the third constructor has 2 parameters of types <em>int</em> and <em>String</em>.
There's MANY things that count as computer issues.
1) when your computer freezes.
2) When your computer runs slow.
3) when your computer takes hours to download, but never does.
4) Glitches (that can lead to crashes).
5) it could be an internal server error.
Need more or this good?
Answer:
#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
char Keep_Going = '-';
int nextBid = 0;
srand(5);
while (Keep_Going != 'n') { //<-- solution
nextBid = nextBid + (rand()%10 + 1);
cout << "I'll bid $" << nextBid << "!" << endl;
cout << "Continue bidding? ";
cin >> Keep_Going;
}
cout << endl;
return 0;
}
Answer:
This is the required code:
Explanation:
public class NumberToString {
public static String numToString(int num, int base) {
final String digits = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
if (num < base) {
return "" + digits.charAt(num);
} else {
return numToString(num / base, base) + digits.charAt(num % base);
}
}
}
