<span>make periodic adjustments on an as-needed basis. </span>
Answer:
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Explanation:
good luck have a nice day
Answer:
PROGRAM QuadraticEquation
Solver
IMPLICIT NONE
REAL :: a, b, c
;
REA :: d
;
REAL :: root1, root2
;
//read in the coefficients a, b and c
READ(*,*) a, b, c
WRITE(*,*) 'a = ', a
WRITE(*,*) 'b = ', b
WRITE(*,*) 'c = ', c
WRITE(*,*)
// computing the square root of discriminant d
d = b*b - 4.0*a*c
IF (d >= 0.0) THEN //checking if it is solvable?
d = SQRT(d)
root1 = (-b + d)/(2.0*a) // first root
root2 = (-b - d)/(2.0*a) // second root
WRITE(*,*) 'Roots are ', root1, ' and ', root2
ELSE //complex roots
WRITE(*,*) 'There is no real roots!'
WRITE(*,*) 'Discriminant = ', d
END IF
END PROGRAM QuadraticEquationSolver
Answer:
The answer is "option B".
Explanation:
In the given code, four double variable "len1, len2, len3, and total" is declared, in which the first three variables accept some value, and in the total variable, we add those variable. In the next step, an integer variable minLength is defined, which converts the decimal value to an integer and adds the value that is "0.5". In this section, the code uses as an intended purpose but only if the total of 3 lengths is equivalent to or larger then 0.5, and wrong choices can be described as follows:
- In option A, It accepts the negative value, that's why it is wrong.
- Option C, Option D, and Option E all were wrong because the code segment is work as intended.
