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lutik1710 [3]
2 years ago
5

Please help on number 7

Mathematics
2 answers:
creativ13 [48]2 years ago
8 0

Answer:

If you told me how to put this into math w ay as a equation, I would be glad to solve it for you... I will edit this once I find the right answer! Sorry I couldn't find it right away :(

Step-by-step explanation:

Edit= I think is would be around 149.328 grams because 56 is 62.22 percent of 90 and 62.22 percent of 240 is 149.328. If this is incorrect I apologize in advance!

Roman55 [17]2 years ago
7 0
U would do 240/90 then that is 2.6 so that is the answer
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Plz help asap with explanation and will get the brilliant
Elina [12.6K]
3x + y = -3
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Use elimination method
Subtract both equations
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3(-2) + y = -3
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8 0
2 years ago
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Solve with work shown. X/3+6 equals -6
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We start out with x/3+6=-6. Subtract 6 from both sides, and you get x/3=-12. Multiply the equation by three and you get x=-36. x=-36 should be your final answer.
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3 years ago
Complete the given diagram by dragging expressions to each leg of the triangle. Then, correctly complete the equation to derive
Nimfa-mama [501]

The equation to derive the distance d is \sqrt{(x2-x1)^2+(y2-y1)^2}. The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = \sqrt{(x2-x1)^2+(y2-y1)^2}

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

d = \sqrt{(x2-x1)^2+(y2-y1)^2}

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= \sqrt{(x2-x1)^2+(y1-y1)^2}

= \sqrt{(x2-x1)^2+0}

= (x2-x1)

Length of the opposite side: (x2, y1) to (x2, y2)

= \sqrt{(x2-x2)^2+(y2-y1)^2}

= \sqrt{0+(y2-y1)^2}

= (y2-y1)

Therefore, the derived distances for the given triangle are:

d=\sqrt{(x2-x1)^2+(y2-y1)^2}, (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

brainly.com/question/661229

#SPJ1

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2 years ago
A RIGHT triangle has two other angles measuring x and 2x. What does x equal?
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Answer:

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