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12345 [234]
3 years ago
9

A and B start from the same point and travel west and north, respectively. A travels 3 miles per hour faster than B. At the end

of two hours, they are 30 miles apart. Find their distances.
Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0

Answer:

Step-by-step explanation:

I believe you're actually looking for their respective rates.  If A travels directly west and B travels directly north, and the distance between them is 30 miles, what we have is a right triangle situation.  The hypotenuse of the triangle is 30.  If the distance an object travels at a certain rate for given time is d = rt, then for B, our formula for distance is d = 2r (since the time each traveled is 2 hours).  A traveled 3 miles per hour faster, so the formula for distance for A is d = (r + 3)2.  Again, each traveled for 2 hours, so t = 2.  Distributing we get that d = 2r + 6.  Now that we have each expression for A and B, we use them in Pythagorean's Theorem to find the only unknown we have which is r.  That's why I said in the beginning that I believe what you're actually looking for is the rate that each traveled.  Our equation is:

30^2=(2r+6)^2+(2r)^2 and

900=4r^2+24r+36+4r^2 and

900=8r^2+24r+36

Putting everything on one side and setting the quadratic equal to 0 to factor, we get

8r^2+24r-864=0

You can factor out an 8 to make the numbers a bit smaller:

8(r^2+3r-108)=0

Factor to get

8(r - 9)(r + 12)=0

That means, by the Zero Product Property, that 8 = 0, r - 9 = 0, or r + 12 = 0.  We all know that 8 doesn't = 0, so forget that one!! If r - 9 = 0, then r = 9.  If r + 12 = 0. then r = -12.  We all know that rate cannot be negative (velocity can, but we are not using vector math here), so we discount rate as -12.  That means that r = 9.  B's rate is 9 then and A's rate is 12.  There you go!

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A collection of coins consists of nickels, dimes, and quarters. There are three fewer quarters than nickels and six more dimes t
weeeeeb [17]

Answer:

You have 15 dimes. You have 9 quarters. You have 12 nickels

Step-by-step explanation:

lets set some variables:

let "n" = the number of nickels

let "d" = the number of dimes

let "q" = the number of quarters

So, the total amount of money you have should be: $4.35 = 0.25q + 0.10d + 0.05n

Now let's look at the relationships between the coins:

"There are three fewer quarters than nickels": n - 3 = q

"six more dimes than quarters": q + 6 = d

So now you have three equations with three variables, all you need to do is solve.

\left \{ {{4.35 = 0.25q + 0.10d + 0.05n} \atop {n - 3 = q}} \atop {q + 6 = d}}\right.

first, you can substitute "n-3" for "q" (according to the 2nd equation) in the 1st and 3rd equation, you get:

\left \{ {{4.35=0.25(n-3)+0.10d+0.05n} \atop {(n-3)+6=d}} \right.

You now only have two equations and two variables.

Simplify:

\left \{ {{4.35=0.25n-0.75+0.10d+0.05n} \atop {n+3=d}} \right.

\left \{ {{4.35=0.30n-0.75+0.10d} \atop {n+3=d}} \right.

Now substitute "n+3" for "d" (according to the 2nd equation) in the 1st equation:

4.35=0.30n-0.75+0.10(n+3)

simplify:

4.35=0.30n-0.75+0.10n+0.30

4.35=0.40n-0.45

4.35+0.45=0.40n

4.80=0.40n

n=12

You have 12 nickels. Now sub "n" back into your equations to find the number of dimes and quarters:

n - 3 = q

12 - 3 = q

q = 9

You have 9 quarters.

q + 6 = d

9 + 6 = d

d = 15

You have 15 dimes.

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Answer:

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Step-by-step explanation:

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