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Ganezh [65]
3 years ago
13

9. Sarah has to create a floral arrangement out of twigs and flowers that has a total of 9 objects. She has to

Mathematics
1 answer:
noname [10]3 years ago
6 0

Answer:

tu debes de saber por qué si yo lo sé tú también no es verdad

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Solve for w.<br> 3w = 3.84
Katen [24]

Answer:

w = 1.28.

Step-by-step explanation:

To find 'w', simply divide the answer by the coefficient.

3.84/3=1.28

w=1.28

REMEMBER: ANYTIME YOU SEE A COEFFICIENT AND A VARIABLE, YOU MUST MULTIPLY THE COEFFICIENT AND THE VARIABLE.

We can check our answer by multiplying.

3*1.28 = 3.84.

Therefore, w = 1.28.

7 0
3 years ago
Read 2 more answers
The two rectangular prisms are similar. What is the volume of the larger rectangular prism?
Brums [2.3K]

The question is missing the figure which is attached below.

Answer:

1620 cm³

Step-by-step explanation:

Given:

The two prisms are similar.

Volume of the smaller prism (V₁) = 60 cm³

Length of the smaller prism (l₁) = 5 cm

Length of the larger prism (l₂) = 15 cm

Now, we know that, for similar figures, the dimensions of the figure are in proportion to each other. Therefore,

\frac{l_2}{l_1}=\frac{b_2}{b_1}=\frac{h_2}{h_1}=k(constant)\\\\Where,\\b_1,b_2\to\ widths\ of smaller\ and\ larger\ prisms\ respectively\\\\h_1,h_2\to\ heights\ of\ smaller\ and\ larger\ prisms\ respectively

\frac{l_2}{l_1}=\frac{15\ cm}{5\ cm}=3\\\\\therefore\ k=3

This means that, the smaller figure is dilated by a scale factor of 3.

Hence, l_2=3l_1,b_2=3b_1,h_2=3h_1

Volume of smaller prism is given as:

V_1=l_1b_1h_1\\\\l_1b_1h_1=60\ cm^3

Volume of larger prism is given as;

V_2=l_2b_2h_2\\\\V_2=3l_1\times 3b_1\times 3h_1\\\\V_2=27(l_1 b_1h_1)\\\\V_2=27\times 60=1620\ cm^3\ \ \ \ [\because\ l_1b_1h_1=60\ cm^3]

Therefore, the volume of the larger rectangular prism is 1620 cm³.

4 0
3 years ago
An urn contains 8 red chips, 10 green chips, and 2 white chips. A chip is drawn and replaced, and then a second chip is drawn.
Harlamova29_29 [7]

Answer:

(A) 0.04

(B) 0.25

(C) 0.40

Step-by-step explanation:

Let R = drawing a red chips, G = drawing green chips and W = drawing white chips.

Given:

R = 8, G = 10 and W = 2.

Total number of chips = 8 + 10 + 2 = 20

P(R) = \frac{8}{20}=\frac{2}{5}\\P(G)=  \frac{10}{20}=\frac{1}{2}\\P(W)=  \frac{2}{20}=\frac{1}{10}

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.

(A)

Compute the probability of selecting a white chip on the first and a red on the second as follows:

P(1^{st}\ white\ chip, 2^{nd}\ red\ chip)=P(W)\times P(R)\\=\frac{1}{10}\times \frac{2}{5}\\ =\frac{1}{25} \\=0.04

Thus, the probability of selecting a white chip on the first and a red on the second is 0.04.

(B)

Compute the probability of selecting 2 green chips:

P(2\ Green\ chips)=P(G)\times P(G)\\=\frac{1}{2} \times\frac{1}{2}\\ =\frac{1}{4}\\ =0.25

Thus, the probability of selecting 2 green chips is 0.25.

(C)

Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

P(2^{nd}\ red\ chip|1^{st}\ white\ chip)=\frac{P(2^{nd}\ red\ chip\ \cap 1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\=\frac{P(2^{nd}\ red\ chip)P(1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\= P(R)\\=\frac{2}{5}\\=0.40

Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.

6 0
3 years ago
Simplify the given equation 5x+2(x-3)=-2(x-1)
olga_2 [115]

Answer:

x =8/9 i dont know if im correct

7 0
3 years ago
Melissa has three different positive integers. she adds their reciprocals together and gets a sum of 1. what is the product of h
madreJ [45]

First let us assign the three positive integers to be x, y, and z.

From the given problem statement, we know that:

(1/x) + (1/y) + (1/z) = 1

<span>
</span>Without loss of generality we can assume x < y < z.

We know that:

 

1 = (1/3) + (1/3) + (1/3)

 

Where x = y = z = 3 would be a solution

 

<span>However this could not be true because x, y, and z must all be  different integers.  And x, y, and z cannot all be 3 or bigger than 3 because the sum would then be less than 1.  So let us say that x is a denominator that is less than 3.   So x = 2, and we have:</span>

 

(1/2) + (1/y) + (1/z) = 1

 

Therefore

 

(1/y) + (1/z) = 1/2

 

<span>We  also know that:</span>

 

(1/4) + (1/4) = (1/2)

 

<span>and y = z = 4 would be a solution, however this is also not true because y and z must also be different. And y and z cannot be larger than 4,  so y=3, therefore</span>

 

(1/2) + (1/3) + (1/z) = 1

 

Now we are left by 1 variable so we calculate for z. Multiply both sides by 6z:

3z + 2z + 6 = 6z

z = 6

 

Therefore:

 

(1/2) + (1/3) + (1/6) = 1

 

<span>so {x,y,z}={2,3,6}  </span>

<span> </span>

8 0
3 years ago
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