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deff fn [24]
3 years ago
8

Angelo, Brandon, and Carl work in the same office. Angelo’s age is 4 years more than twice Carl’s age. Brandon is 5 years younge

r than Carl. The average of the three ages is 41.
Part A: Use a variable to define the age of one of the men.

Part B: Use the variable in part A to represent the ages of the other two men.

Part C: Write an equation that represents the average of the three men's ages equivalent to 41.

Part D: Find the age of each of the men.
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

Angelo is 66 Brandon is 26 Carl is 31

Step-by-step explanation:

Variables a=Angelo b=Brandon c=Carl

Equation (1/3)(a+b+c) = 41

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Chelsea and her friends are making small fruit baskets for their neighbors. They have 90 pears, 45 peaches, and 75 apples. What
iVinArrow [24]

Answer:

15 baskets

Step-by-step explanation:

This question is a GCF question

The first step would be to find the factors of 45, 75 and 90

The factors of 45 are: 1, 3, 5, 9, 15, 45

The factors of 75 are: 1, 3, 5, 15, 25, 75

The factors of 90 are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

The greatest common factor is 15.

Therefore, the greatest number of baskets they can make if each basket has the same number of pears, the same number of peaches, and same number of apples, with no fruit leftover is 15 baskets

3 0
3 years ago
The owner of a flower shop sells 18 roses gor 90$ what is the cost in dollars per rose
Sunny_sXe [5.5K]
The equation would be 90/18 which would give you the cost of 5 dollars per rose
4 0
3 years ago
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The product of x and the sum of 6 and 8 times the square of x
Vaselesa [24]

Answer:

x(6 + 8x²) or 6x + 8x³.

Step-by-step explanation:

"The square of x" can be represented by x² and 8 times that would be 8 * x² or 8x². The sum of 6 and 8x² can be represented by 6 + x² and the product of x and 6 + x² can be represented by x * (6 + 8x²) or x(6 + 8x²) which simplifies to 6x + 8x³.

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Jack's mother gave him 50 chocolates to give to his friends at his birthday party. He gave 3 chocolates to each of his friends a
djverab [1.8K]

50 = 3x + 2

50 - 2 = 3x

48 = 3x

48/3 = 3x/3

16 = x


Jack has 16 friends.

4 0
2 years ago
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The degenerative disease osteoarthritis most frequently affects weight-bearing joints such as the knee. Two random samples from
Vinvika [58]

Answer:

t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771  

df=n_1 +n_2 -2=13+19-2=30  

Since is a right tailed test the p value would be:  

p_v =P(t_{30}>1.771)=0.0434  

Comparing the p value with the significance level \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

Step-by-step explanation:

Data given

\bar X_{1}=810 represent the mean for sample 1  

\bar X_{2}=770 represent the mean for sample 2  

s_{1}=67 represent the sample standard deviation for 1  

s_{2}=56 represent the sample standard deviation for 2  

n_{1}=13 sample size for the group 2  

n_{2}=19 sample size for the group 2  

\alpha=0.05 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for category 1 is higher than the mean for category 2, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=13+19-2=30  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771  

P value  

Since is a right tailed test the p value would be:  

p_v =P(t_{30}>1.771)=0.0434  

Comparing the p value with the significance level \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

4 0
3 years ago
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