The cross-section cut by the plane yields a quadrilateral with length and width equal to the length and width of the face that is parallel to the plane.
W=wind p + w=158...p=158-w p-w=112...p=112+w SO 158-w=112+w 46=2w 23=w SO in conclusion you have the correct answer of wind being 23km/h while the plane is going 135 km/h
