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3 years ago

Can someone help me out?

Mathematics

2 answers:

grandymaker [24]3 years ago

7 0

Answer:

Step-by-step explanation:

please mark me brainliest and 5 star

OleMash [197]3 years ago

7 0

Answer:

Step-by-step explanation:

You add all the sides together hope it helps pls mark brainliest

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NUMBER 4 DO ANYONE KNOW IT PLEASE HELP

ss7ja [257]

Answer:

The Height of the cliff is 41.5 meters tall.

Option B. 41.5 meters.

Step-by-step explanation:

Given:

AB = 85 meter

Angle of elevation ∠ C= 26°

To Find:

Cliff height = AB = ?

Solution:

In right angle Triangle ABC by tangent Identity we have

$\tan C = \frac{\textrm{side opposite to angle C}}{\textrm{side adjacent to angle C}}$

Substituting the given values we get

$\tan 26 = \frac{AB}{BC}=\frac{AB}{85}$

$\therefore AB=85\times 0.4877=41.45=41.5\ meters$

The Height of the cliff is 41.5 meters tall.

7 0

2 years ago

In scientific notation is 14,200 000 becomes 1.42 x10'5

lyudmila [28]

You are correct with the 1.42 but wrong with the 10^5
Count the digits after the 1, which is 7. So it should be
1.42 x 10^7

6 0

3 years ago

5) Jim is hoping that a park will be built

Sedaia [141]

Answer:

Step-by-step explanation:

7 0

2 years ago

Help me please i don't know what i'm doing please help

UNO [17]

Answer: -1/9

Step by step explanation:

The common difference of an arithmetic sequence can be found by picking 2 consecutive terms, and subtracting the second from the first. For example, if I chose the terms 2 and 1 8/9, I would find the common difference by:

1 8/9 - 2, which is equal to -1/9.

You can confirm this by picking another pair of consecutive terms. Let's pick 1 7/9 and 1 2/3:

1 2/3 - 1 7/9 = -1/9, as 1 2/3 = 1 6/9, so 1 6/9 - 1 7/9 = -1/9

8 0

3 years ago

The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re

Zolol [24]

Answer:

a) $df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

3 0

3 years ago