I think it must be the right triangle so
x=height of the antenna
tan(66)=x/50
x=50*tan(66)
x=1.33 ft
->the height of the antenna = 1.33 ft
hope it is the correct answer because you didn't provided me enough information.
Here is the solution based on the given problem above.
Given: Area of the piece of paper = 84 square inches
Width = 10 1/2 or 10.5 inches long
? = length of the piece of paper
To find the area of an object, the formula would be A= L x W
Now, let's substitute the given values above
84in2 = L(10.5in)
Now, divide both sides with 10.5 and we get 8.
L = 8 inches.
Therefore, the length of the paper is 8 inches.
Hope this solution helps.
A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
Answer:
4+m=4m
Step-by-step explanation:
Because 4 plus m is 4m
