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Bess [88]
3 years ago
13

What is the dergee of the monomial 5x^6y^3

Mathematics
2 answers:
mash [69]3 years ago
8 0
The degree of the monomial is 6.
Hope I helped!
Mekhanik [1.2K]3 years ago
8 0
The degree is 9. for monomials, you add all the degrees of variables together. 6+3=9
You might be interested in
(MUST SHOW WORKING)
myrzilka [38]
First of all, keep in mind :
m --> cm = times by 100
cm --> mm = times by 10
mm --> cm = divide by 10
cm --> m = divide by 100

so we know that a square has 4 equal sides and to find the area of a square we do base*height. now these two numbers on the base and height are the same so we're basically squaring them to get the area of 81. therefore, we do the reverse so square root 81 and we get the answer 9cm

now let's convert 9cm to mm
= 9*10 = 90
area in mm = 90mm

now let's convert 9cm to meters
= 9/100=0.09
area in m = 0.09m

and finally, we already worked out the area in cm
= 9cm

hope this helped :)


3 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-22x%3D10%5C%5C" id="TexFormula1" title="x^{2} -22x=10\\" alt="x^{2} -22x=10\\"
Ronch [10]

Answer:

Step-by-step explanation:

x^2 - 22x = 10

Next step is to complete the square on the left hand side of the equation and it would be balanced by adding the same number to the right side of the equation. It becomes

x^2 - 22x + (22/2)^2 = 10 + (22/2)^2

x^2 - 22x + (11)^2 = 10 + (11)^2

x^2 - 22x + (11)^2 = 10 + 121

x^2 - 22x + (11)^2 = 131

x^2 - 22x + 121^2 = 131

(x - 11)^2 = 131

Taking square root of both the left hand side and the right hand side of the equation, it becomes

x - 11 = ±√131

x - 11 = ±11.45

Adding 11 to the left hand side and the right hand side of the equation, it becomes

x - 11 + 11 = ±11.45 + 11

x = 11.45 + 11 or x = -11.45 + 11

x = 22.45 or x = - 0.45

5 0
3 years ago
Please help me<br> Show your work
GrogVix [38]

<u>ANSWER TO PART A</u>

The given triangle has vertices J(-4,1), K(-4,-2),L(-3,-1)


The mapping for rotation through 90\degree counterclockwise has the mapping


(x,y)\rightarrow (-y,x)


Therefore

J(-4,1)\rightarrow J'(-1,-4)


K(-4,-2)\rightarrow K'(2,-4)


L(-3,-1)\rightarrow L'(1,-3)


We plot all this point and connect them with straight lines.


ANSWER TO PART B


For a reflection across the y-axis we negate the x coordinates.


The mapping is



(x,y)\rightarrow (-x,y)


Therefore

J(-4,1)\rightarrow J''(4,1)


K(-4,-2)\rightarrow K''(4,-2)


L(-3,-1)\rightarrow L''(3,-1)


We plot all this point and connect them with straight lines.


See graph in attachment







7 0
3 years ago
A kite flying in the air has an 11 - ft line attached to it. Its line is pulled taut and casts an 8 - ft shadow. Find the height
Fofino [41]
The line, shadow and the height form a right angled triangle so we can apply the Pythagoras theorem here:-

11^2 = h^2 + 8^2       where h = height of the kite
h^2 = 11^2 - 8^2
h^2 = 57
h = 7.55 ft to the nearest foot   Answer
5 0
3 years ago
Read 2 more answers
An electronics store had a special sale on two different models of calculators. The more high-tech model sold for $33.02 and
neonofarm [45]

Answer:

$736.45/$33.02 = 22.30 high tech

x($33.02) = $736.45

$736.45/$18.55 = 39.70 older models

y($18.55) = $736.45

3 0
2 years ago
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