11) -x + y = -1 ; 2x - y = 0
y = -1 + x ; 2x - (-1+x) = 0 ⇒ 2x + 1 - x = 0 ⇒x = -1
y = -1 + (-1) ⇒ y = -2
12) -2x + y = -20 ; 2x + y = 48
y = -20 + 2x ; 2x + (-20 + 2x) = 48 ⇒ 2x -20 + 2x = 48 ⇒ 4x = 48 + 20
4x = 68 ⇒ x = 68/4 ⇒ x = 17
y = -20 + 2(17) ⇒ y = -20 + 34 ⇒ y = 14
13) 3x -y = -2 ; -2x + y = 3
y = 3 + 2x ; 3x - (3 + 2x) = -2 ⇒ 3x - 3 - 2x = -2 ⇒ x = -2 + 3 ⇒ x = 1
y = 3 + 2(1) ⇒ y = 3 + 2 ⇒ y = 5
14) x - y = 4 ; x - 2y = 10
x = 4 + y ; (4 + y) - 2y = 10 ⇒ 4 + y - 2y = 10 ⇒ 4 - y = 10
⇒ -y = 10 - 4 ⇒ -y = 6 ⇒ y = -6
x = 4 + (-6) ⇒ x = 4 - 6 ⇒ x = -2
15) x + 2y = 5 ; 3x + 2y = 17
x = 5 - 2y ; 3(5-2y) + 2y = 17 ⇒ 15 - 6y + 2y = 17 ⇒ -4y = 17 - 15
⇒ -4y = 2 ⇒ y = -2/4 ⇒ y = -1/2
x = 5 - 2(-1/2) ⇒ x = 5 + 2/2 ⇒ x = 5 + 1 ⇒ x = 6
Answer:
Use the graph to write a linear function that relates y to x. The points lie on a line. Find the slope and y-intercept of the line. Because the line crosses the y-axis at (0, −3), the y-intercept is −3.w
Step-by-step explanation:
There are three standard forms for linear functions y = f(x):
f(x) = mx + b (The "slope-intercept" form),
y - yo = m(x - x0) or, equivalently, f(x) = y0 + m(x - x0) (The "point-slope" or "Taylor" form), and.
Ax + By = C (The "general form") which defines y implicitly as a function of x as long as B 0.
The greatest common fact or 32 and 96 is 2
Answer:
The answer is 30
Step-by-step explanation:
First you have to find 120% of a (12).
Therefore; 14.4 is 80% of b, and we are trying to find 100% of b
we do not know what is 100% therefore we call it *x*. In order to find this unknown value *x* we cross multiply.
This is the same as saying;
100% percent would be 1 because it is the whole number we are trying to find. The 80% would be 4/5. To get 4/5 you can simply break down 80/100 ( this is 80% as a fraction).
so the new equation is: 14.4= 4/5x
We divide both sides by 4/5. Then we will get x tobe equal to 18. Therefore b is 18. We were asked to find (a + b) so.<em> </em><em>1</em><em>8</em><em>+</em><em>1</em><em>2</em><em> </em><em>=</em><em> </em><em>30</em>
