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pantera1 [17]
3 years ago
11

Kendra is saving money to go buy a new bike. She needs at least $120. Her mom gave her $25 to get started. Let m represent the a

mount of money Kendra still needs to save.
Mathematics
2 answers:
Vanyuwa [196]3 years ago
8 0

Answer:

Kendra still need at least at least 95 dollars for her bike

Alexxx [7]3 years ago
6 0
Kendra needs to save $95
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A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
Which expression is equivalent to 6t⁻⁷x 3 t⁵
aleksandrvk [35]
6t^-7 * 3t^5 = 1/6t^7 * 3t^5
6 0
2 years ago
How does Mr. Peters get to ask for three wishes?
satela [25.4K]

Answer:

find a Jennie

Step-by-step explanation:

just don't expect him to grant you more wishes if that's one of your wishes

8 0
3 years ago
splashtown charges an entrance fee of $25 plus $1 for each ride. Schlitterbahn charges a $40 entrance fee and all the rose are f
laila [671]
Splashtown: 25 + 1x
Schlitterbahn: 40
25 + 1x = 40
-25 -25
0 1x = 15
x = 15
So after 15 rides, Schlitterbahn would be cheaper than Splashtown.
8 0
3 years ago
Simplify.<br> 3sqrt -64m^15n^3<br><br> -8m^5<br> -8m^5n<br> -4m^5n<br> -4m^5
makkiz [27]

Answer:

-4m^5n

Step-by-step explanation:

∛-64 = -4

\sqrt[3]{m^{15}} =m^5

∛n³ = <em>n</em>

8 0
3 years ago
Read 2 more answers
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