Please help will mark BRAINLIEST

Mathematics

1 answer:

Harman [31]3 years ago

6 0

Answer:

Yes both triangles are congruent thanks to SAS

we know XL and BC are congruent and AB and QX are congruent and the degrees are also congruent, since the angle is between the sides it's Side-Angle-Side(SAS)

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Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule

Sergeeva-Olga [200]

Answer:

First term: 5

Fourth term: 5 1/2

Tenth term: 6 1/2

Step-by-step explanation:

Let's find the first, fourth and tenth terms of the arithmetic sequence described by the given rule:

A(n) = 5 + (n-1) (1/6)

First term:

A(1) = 5 + (1-1) (1/6)

A(1) = 5 + (0) (1/6)

A(1) = 5

Fourth term:

A(4) = 5 + (4-1) (1/6)

A(4) = 5 + (3) (1/6)

A(4) = 5 + 3/6 = 5 3/6 = 5 1/2 (simplifying)

Tenth term:

A(10) = 5 + (10-1) (1/6)

A(10) = 5 + (9) (1/6)

A (10) = 5 + 9/6 = 6 3/6 = 6 1/2 (simplifying)

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4 years ago

The graph below shows the function f(x)=x-3/x2-2x-3. Which statement is true?

BARSIC [14]

1. Domain.

We have $x^2-2x-3$ in the denominator, so:

$x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\
(x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}$

So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.

2. Asymptotes:

$f(x)=\dfrac{x-3}{x^2-2x-3}=\dfrac{x-3}{(x-3)(x+1)}=\boxed{\dfrac{1}{x+1}}$

We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)

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3 years ago

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Answer: 2654

Step-by-step explanation:

you take jolly's number 4599 and subtract Gopal's number of 1945

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2 years ago

Preston started the summer owing $15 to his brother and $20 to his sister. He earned $75 mowing lawns, and paid his brother and

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