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Anna [14]
4 years ago
9

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule

Mathematics
1 answer:
Sergeeva-Olga [200]4 years ago
5 0

Answer:

First term: 5

Fourth term: 5 1/2

Tenth term: 6 1/2

Step-by-step explanation:

Let's find the first, fourth and tenth terms of the arithmetic sequence described by the given rule:

A(n) = 5 + (n-1) (1/6)

First term:

A(1) = 5 + (1-1) (1/6)

A(1) = 5 + (0) (1/6)

A(1) = 5

Fourth term:

A(4) = 5 + (4-1) (1/6)

A(4) = 5 + (3) (1/6)

A(4) = 5 + 3/6 = 5 3/6 = 5 1/2 (simplifying)

Tenth term:

A(10) = 5 + (10-1) (1/6)

A(10) = 5 + (9) (1/6)

A (10) = 5 + 9/6 = 6 3/6 = 6 1/2 (simplifying)

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Which relationship describes angles 1 and 2
solong [7]
A. Vertical angles.

Complementary angles are adjacent angles that add to equal 90 degrees.
Adjacent angles are angles that share a side (they are right next to each other).
Supplementary angles are adjacent angles that add to equal 180 degrees.

Thus the answer is A.

Hope this helps.
7 0
3 years ago
ASAP math help algebra plzzz
skelet666 [1.2K]
This is a geometric sequence because each term is a constant multiple, called the common ratio, of the previous term.  In this case the common ratio, noted as "r", is:

8/-2=-32/8=128/-32=r=-4

The first term is -2

Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number.

Since we know r and a for this problem already we can say:

a(n)=-2(-4)^(n-1)
6 0
4 years ago
Help me and be Brainiest
Snowcat [4.5K]

1. D) 5 1/4

2. C) 44/9

3.

4.

5. A) 1 1/2


4 0
3 years ago
PLEASE HELP ASAP, PUT INTO NORMAL NUMBERS, STANDARD FORM?
Masteriza [31]

Given:

The numbers are written in scientific notation.

To find:

The standard form of given numbers.

Solution:

Formula used:

a^{-n}=\dfrac{1}{a^n}

(a)

7.2\times 10^{-8}=7.2\times \dfrac{1}{10^8}

7.2\times 10^{-8}=\dfrac{7.2}{1000000000}

7.2\times 10^{-8}=0.000000072

(b)

6.3\times 10^{-9}=6.3\times \dfrac{1}{10^9}

6.3\times 10^{-9}=\dfrac{6.3}{10000000000}

6.3\times 10^{-9}=0.0000000063

(c)

4.54\times 10^{-5}=4.54\times \dfrac{1}{10^5}

4.54\times 10^{-5}=\dfrac{4.54}{100000}

4.54\times 10^{-5}=0.0000454

(d)

7.041\times 10^{-10}=7.041\times \dfrac{1}{10^{10}}

7.041\times 10^{-10}=\dfrac{7.041}{100000000000}

7.041\times 10^{-10}=0.0000000007041

Therefore, 7.2\times 10^{-8}=0.000000072, 6.3\times 10^{-9}=0.0000000063, 4.54\times 10^{-5}=0.0000454,

7.041\times 10^{-10}=0.0000000007041.

8 0
3 years ago
Please help in math : lenght of rectangle is width+7m.
dexar [7]

L=W+7

W=1/3L

we can substitute the width in the first relation with 1/3L

L=1/3L+7

we move1/3L to the left

L-1/3L=7

we multiply by 3 to remove the denominator

3L-L-21

2L=21

L=21/2=10.5cm

8 0
3 years ago
Read 2 more answers
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