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marta [7]
3 years ago
12

16. How many different words can be formed with the letters of the word 'RAJARAM'? In how many of

Mathematics
2 answers:
Mandarinka [93]3 years ago
7 0

Answer:

The word "ARRANGE" can be arranged in

2!×2!

7!

=

4

5040

=1260 ways.

For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.

Then the number of ways =

2!

6!

=360.

The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.

Also in the same way, the number of ways where two "A's" are together is 360.

The number of ways where two "A's" and two "R's" are together is 5!=120.

The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.

Step-by-step explanation:

<h2><u>PLEASE</u><u> </u><u>MARK</u><u> ME</u><u> BRAINLIEST</u><u> AND</u><u> FOLLOW</u><u> ME</u><u> LOTS</u><u> OF</u><u> LOVE</u><u> FROM</u><u> MY</u><u> HEART'AND</u><u> SOUL</u><u> DARLING</u><u> TEJASVINI</u><u> SINHA</u><u> HERE</u><u> ❤️</u></h2>
DanielleElmas [232]3 years ago
3 0
(i) Take RRJ out and the rest letter is AAAM and permutation wise it should form 4! variations, may the 3As being Afirst, Asecond, and Athird. These three alone may form 3! permutations and when setting Afirst = Asecond =Athird one would have 3! sets of identical variations so 4!/3! = 4. And intuitively we can already see them: AAAM, AAMA, AMAA and MAAA. While inserting anything (in our case RRJ) back into a 4 letter queue, there are exactly 4+1 spots to insert (before every letter + behind the last letter) so for RRJ there would be 4*(4+1) variations which is 20. If considering RJR or JRR also applies to the answer, 20+20+20=60.
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Christopher is going to install wallpaper on the four walls of his room. Two of the walls are 14 feet long by 9 feet high. The o
Debora [2.8K]
2 of the walls are 14 ft by 9 ft....
A = L * W
A = 14 * 9 = 126 sq ft.....and since there is 2 of them...2(126) = 252 sq ft

2 of the walls are 20 ft by 9 ft
A = L * W
A = 20 * 9
A = 180 sq ft....and since there are 2 of them ..2(180) = 360 sq ft

so for all 4 walls, we have : 252 + 360 = 612 sq ft

54 * 11 = 594 sq ft...so we need 11 double rolls...which costs 11(40) = $ 440
18 * 1 = 18 sq ft ....and we need 1 single roll...which costs $ 20

so we have 612 sq ft to cover....11 double rolls cover 594 sq ft and cost 440...and 1 single roll which covers 18 sq ft and cost 20
for a total cost of : $ 460 <==




8 0
4 years ago
@assessment Jane has 10 dolls.
marta [7]
The answer is 10 - 7 = 3
5 0
3 years ago
Read 2 more answers
List the ordered pairs and determine whether or not this is a function
Ahat [919]
The ordered pairs are (1,-1) (1,-2) (2,-3) (2,-4).

This is not a function because in order to be a function, every x value needs to have one and only one y value. You can see here that the x values have two y values, so it is not a function.
5 0
3 years ago
What is 11.52/128 show your work
grandymaker [24]

Answer:

The answer is

<h2>9/100</h2>

Step-by-step explanation:

11.5/128

First convert the decimal to an improper fraction

That's

11.52 =  \frac{288}{25}

So we have

\frac{288}{25}  \div 128

Change the division sign to multiplication sign and reverse the second number

That's

\frac{288}{25}  \times  \frac{1}{128}

Simplify

\frac{288}{3200}

Divide through by 32

The final answer is

\frac{9}{100}

Hope this helps you

6 0
4 years ago
What is the value of the expression below when w =<br> = 22<br> 8w + 10
dalvyx [7]

Answer: 186

Step-by-step explanation:

To find the value, we plug in w=22 and solve.

8(22)+10          [multiply]

176+10             [add]

186

Now, we know the value is 186.

7 0
3 years ago
Read 2 more answers
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