Answer:
see explanation
Step-by-step explanation:
Sum the 3 consecutive integers and equate to 36
x + x + 2 + x + 4 = 36
3x + 6 = 36 ( subtract 6 from both sides )
3x = 30 ( divide both sides by 3 )
x = 10
The 3 consecutive integers are
10, 10 + 2, 10 + 4, that is
10, 12, 14
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
turn the fractions into decimals
7/20 = 0.35
1/5 = 0.20
the answer is
0.38 then 7/20 then 0.34 then 1/5
Split it up
3x^2+12x-5x-20
group
(3x^2+12x)+(-5x-20)
factor
(3x)(x+4)+(-5)(x+4)
undistribute (x+4) like ab+ac=a(b+c)
(3x-5)(x+4)
