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Feliz [49]
3 years ago
11

What is the solution set for |z+4|>15

Mathematics
1 answer:
Contact [7]3 years ago
5 0

Answer:

z + 4 = 15 \\ z + 4 - 4 = 15 \\ z = 15 - 4 \\ z = 11

z>11

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if there’s 12 girls selling cookies that are 2.75 and they need to reach $360 how many boxes would each girl have to sell
Sindrei [870]

Answer:

11 each

Step-by-step explanation:

360/2.75=130.9

rounding up, 131x2.75=360.25

131/12=10.9 boxes each

therefore each girl will have to sell 11 boxes

4 0
3 years ago
Write the next three terms of the arithmetic sequence.
JulijaS [17]

The next three terms are: 1/6 , 0 and -1/6

Step-by-step explanation:

Given sequence is:

\frac{5}{6} , \frac{2}{3} ,\frac{1}{2}, \frac{1}{3} ...

First of all, we have to find the common difference

here\\a_1 = \frac{5}{6}\\a_2 = \frac{2}{3}\\a_3 = \frac{1}{2}\\a_4 = \frac{1}{3}\\d = a_2-a_1 = \frac{2}{3} -\frac{5}{6} = \frac{4-5}{6} = -\frac{1}{6}\\d = a_3 - a_2 = \frac{1}{2} - \frac{2}{3} = \frac{3-4}{6} = =\frac{1}{6}

The common difference is -1/6

We can simply add -1/6 to the previous term to find the next terms so,

Adding -1/6 to 1/3

\frac{1}{3} - \frac{1}{6} = \frac{2-1}{6} = \frac{1}{6}\\\frac{1}{6} - \frac{1}{6} = 0\\0-\frac{1}{6} = -\frac{1}{6}

Hence,

The next three terms are: 1/6 , 0 and -1/6

Keywords: Arithmetic sequence, common difference

Learn more about arithmetic sequence at:

  • brainly.com/question/2495851
  • brainly.com/question/2491745

#LearnwithBrainly

4 0
3 years ago
Which statements about the value of the digits in the number 1,111,111 are true?
seraphim [82]
The answer is A and D
3 0
3 years ago
A train leaves little? rock, arkansas, and travels north at 80 kilometers per hour. another train leaves at the same time and tr
balandron [24]

p(80+60)=560

p(140)=560

560/140 = 4 hours

4 0
3 years ago
In order to qualify for a bowling tournament, bowlers bowl 20 games. The results are normal. The average score was 167 with a st
Ksenya-84 [330]

Answer:

189

Step-by-step explanation:

bc that's just what I think

6 0
3 years ago
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