Which equations have 8 as a solution?
Answers:
15 - n = 7
-15 -15
-n = -8
n = 8
4n = 32
n = 8
Select all the equations that have 8 as a solution.
Answers:
A and C
Explanation is above.
Hope this helps!
Answer:
285.45
Step-by-step explanation:
If you multiply 17.3x16.5, you get 285.45, and when you round to the nearest hundredth, well, it gives you the same answer.
Therefore, the answer is 285.45.
Answer:
Any value of x makes the equation true.
Step-by-step explanation:
all real numbers
interval notation:(-infinity, infinity)
pls mark as brainliest lol
Answer: Solve for Y
y = -16x - 38
And then y intercept is
(0, -38)
Step-by-step explanation:
Answer:
5x^2+22x-12 x cannot be -5, -4, -2
(x+5)(x+4)(x+2)
Step-by-step explanation:
In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:
x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)
x^2 + 7x + 10 <-- This should factor out to (x+5)(x+2)
Now that you have factored out the two quadratics, plug them into the equation.
5x - 3
(x+4)(x+2) (x+5)(x+2)
Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.
5x (x+5) - 3(x+4)
(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)
Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:
5x^2+25x - (3x+12) = 5x^2+22x-12 x cannot be -5, -4, -2
(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)
