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AlekseyPX
2 years ago
10

What is the distance between the point (1,4) and (3,7)

Mathematics
1 answer:
borishaifa [10]2 years ago
7 0

Answer:

POINTS

Step-by-step explanation:

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If you know the answer to this, please say it! Equation and all too! Thank you :DD
vlabodo [156]

Answer

x=33

Step-by-step explanation:

since they're both on the same line we must equal them to 180.

18 + x + 4x -3 = 180 (Now you simplify terms)

5x + 15 = 180 (Subtract the 15 from both sides)

5x = 165 (divide by 5 to isolate the variable)

x = 33 (Hope I was able to help :) )

6 0
3 years ago
there are 3 times more students who play trumpet than the tuba. which expression represents the total number of trumpeters based
beks73 [17]
The equation would look like:
3t
3 0
3 years ago
Read 2 more answers
PLLKEEASE HELPPPPPPP ASAPP
erica [24]

Answer:

x = 19

Step-by-step explanation:

(5x + 4)° + (x - 2)° + (3x + 7)° = 180°

(5x + x + 3x)° + (4 - 2 + 7)° = 180°

9x° + 9° = 180° → ÷9

x + 1 = 20

x = 20 - 1

x = 19

7 0
2 years ago
Which explanation about figures is correct? * A. All rhombuses are parallelograms. Parallelograms have 2 pairs of parallel sides
bezimeni [28]

Answer:

The correct option is;

A. All rhombuses are parallelograms. Parallelograms have 2 pairs of parallel sides. Therefore, all rhombuses have 2 pairs of parallel sides

Step-by-step explanation:

A rhombus is a quadrilateral that has all 4 sides, it has equal opposite angles and perpendicular diagonals that bisect one another  as well as having a pair of opposite parallel sides making it a parallelogram

A rhombus is similar to a parallelogram which also has equal opposite and parallel sided and equal opposite angles and the diagonals of a parallelogram also bisect each other.

4 0
3 years ago
Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).
lutik1710 [3]

Answer:

The arc length is \dfrac{21}{16}

Step-by-step explanation:

Given that,

The given curve between the specified points is

x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}

The points from (\dfrac{9}{16},1) to (\dfrac{9}{8},2)

We need to calculate the value of \dfrac{dx}{dy}

Using given equation

x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}

On differentiating w.r.to y

\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})

\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})

\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})

\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}

We need to calculate the arc length

Using formula of arc length

L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}

Put the value into the formula

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}

L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}

L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}

L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}

L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}

L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}

Put the limits

L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})

L=\dfrac{21}{16}

Hence, The arc length is \dfrac{21}{16}

6 0
3 years ago
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