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2 years ago

Look at the image below for the question !!!!!!

Mathematics

1 answer:

Semenov [28]2 years ago

4 0

Answer:

136 cm2

Step-by-step explanation:

6*2=12 12*2=24

6*7=42 42*2=84

7*2=14 14*2=28

Add.

24+84+28=136

I hope this helps!

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A seven-sided number cube with sides numbered 1-7 is rolled. what is the probability that a 4 or an odd number is rolled.

jeka57 [31]

There’s a 1/7 chance it would roll a 4.

There’s a 4/7 chance it would roll an odd number.

8 0

2 years ago

Is this true?

mars1129 [50]

Answer:

Yes!

Step-by-step explanation:

If you work out the opperation it is true!

(I would do it, but the numbers a really big. :D But trust me i did it and it worked. ^_^)

7 0

3 years ago

When asked to write a point slope equation for a line passing through the points (-4,-7) and (3,2) a student wrote y-2=-9/7(x-3)

AleksAgata [21]

First let's find the slope
Slope formula:
$\frac{y_2-y_1}{x_2-x_1} =slope$
Given the two coordinates:
(-4,-7) (3,2)
x1,y1 x2,y2

Plug these numbers into the formula
$\frac{2-(-7)}{3-(-4)} = \frac{9}{7}$
In this case the mistake that was made was that the student wrote the slope negative instead of positive
Final answer:
y-2=9/7(x-3)

8 0

2 years ago

Trigonometry help please show work. Due soon please help

nexus9112 [7]

Answer:

Step-by-step explanation:

5 0

2 years ago

A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages ar

Elenna [48]

Answer:

We conclude that the mean amount packaged is equal to 8.17 ounces.

Step-by-step explanation:

We are given that in a particular sample of 50 packages, the mean amount dispensed is 8.171 ounces, with a sample standard deviation of 0.052 ounces.

Let $\mu$ = population mean amount packaged.

So, Null Hypothesis, $H_0$ : $\mu$ = 8.17 ounces {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 8.17 ounces {means that the mean amount packaged is different from 8.17 ounces}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean amount dispensed = 8.171 ounces

s = sample standard deviation = 0.052 ounces

n = sample of packages = 50

So, the test statistics = $\frac{8.171-8.17}{\frac{0.052}{\sqrt{50} } }$ ~ $t_4_9$

= 0.1359

The value of t-test statistics is 0.1359.

Also, the P-value of test-statistics is given by;

the meaning of the p-value is that the p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.001 ounces away from8.17 if the null hypothesis is true.

P-value = P( $t_4_9$ > 0.136) = More than 40% {from the t-table}

Since the P-value of our test statistics is more than the level of significance of 0.01, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean amount packaged is equal to 8.17 ounces.

6 0

2 years ago