The larger of the two roots of the equation 
would be 28.59.
<h3>How to find the roots of a quadratic equation?</h3>
Suppose that the given quadratic equation is
Then its roots are given as:
The given quadratic equation is
now, the roots of the equation are
The two roots are 0.27 and 28.59.
Thus, the larger of the two roots of the equation would be 28.59.
Learn more about finding the solutions of a quadratic equation here:
brainly.com/question/3358603
#SPJ1
Answer:
Polymomial with 4 terms i believe
Answer:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.
Step-by-step explanation:
In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.
Let u = 1 + sin(x).
This means du/dx = cos(x). This implies dx = du/cos(x).
Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.
∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))
= ∫(u^(-1/2) * du). Integrating:
(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.
Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!
The answer is 5/4 ....so go for that !!! C
