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7nadin3 [17]
3 years ago
7

(2, StartFraction pi Over 3 EndFraction) is graphed on the polar grid below. On a polar coordinate plane, a point is at (2, Star

tFraction pi Over 3 EndFraction). Which polar coordinates below also represent that point? Check all that apply.
Mathematics
2 answers:
nirvana33 [79]3 years ago
4 0

Answer:

1 3 and 4

Step-by-step explanation:

Doing it on brainly but the other guy gave me the answers lol

katen-ka-za [31]3 years ago
3 0

Answer: 1, 3, 4

1 (2, 7pi/3)

3 (2, -5pi/3)

4 (-2, 4pi/3)

Step-by-step explanation:

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Please help!! 11 points!!
MariettaO [177]

Answer:3x < 8x - 3

Step-by-step explanation:

5 0
4 years ago
X-2y=4 How to solve this
WARRIOR [948]
Since <span>x </span>does not contain the variable to solve for, move it to the right side of the equation by subtracting <span>x</span> from both sides
.−2y=−x+4
divide each term by −2 and simplify.
<span> the answer is y=<span>x/2</span>−<span>2

slope= 1/2
y-intercept = -2</span></span>
4 0
3 years ago
What the expression (4f-3+2g)-(4g+2)
galben [10]
For this question you can say: 
4f -3 +2g - 4g -2
so now you can simplify and find the answer:
4f -3 -2g -2 = 4f -2g -5
and that's the answer :)))
I hope this is helpful
have a nice day 
8 0
3 years ago
If 7 to the second power in parentheses to the X exponent equals 1 what is the value of x
sergey [27]
(7^2)^x = 1
49^x = 1

You should know that anything to the power of 0 is equal to 1, therefore x = 0.

49^0 = 1


Hope that helps :)
8 0
4 years ago
Find the average rate of change of each function over the interval [0, 2]. Match each representation with its respective average
marishachu [46]
Average rate of change over interval [a,b]: r=[f(b)-f(a)]/(b-a)
In this case the interval is [0,2], then a=0, b=2
r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2

1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
r=4

2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
r=(0+10)/2
r=(10)/2
r=5

3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
g(0)=2
r=(6-2)/2
r=(4)/2
r=2

4) Fourth function: j(x)
r=[j(2)-j(0)]/2
From the table:
x=2→j(2)=-8
x=0→j(0)=4
r=(-8-4)/2
r=(-12)/2
r=-6

Answer:
Pairs
1) h(x)     4
2) f(x)      5
3) g(x)     2
4) j(x)     -6
8 0
4 years ago
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