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Hitman42 [59]
3 years ago
5

Help asp, I can’t find the answers:P

Mathematics
1 answer:
zepelin [54]3 years ago
8 0

Answer:

the answer will be B

Step-by-step explanation:

It does increase

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-8m - 12 &gt; -5(m - 8) – 3(m - 7)<br> Write the solution to the inequality
horrorfan [7]

Answer:

No answer.

Step-by-step explanation:

- 8m - 12 > -5m + 40 - 3m + 21

combine terms

-8m - 12 > -8m +61

add 8m to both sides

-12 > 61

negative 12 is not greater than 61

4 0
3 years ago
Can someone help me please, ASAP!!!
slega [8]

Answer:

sorry i need this for a challenge.

Step-by-step explanation:

6 0
3 years ago
Mislabeled seafood In 2013 the environmental group Oceana (usa.oceana.org) analyzed 1215 samples of seafood purchased across the
Step2247 [10]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of all seafood sold in the United States that is mislabeled or misidentified is (0.3036, 0.3564).

<h3>z-distribution interval:</h3>

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

  • In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

For this problem:

  • 1215 samples, hence n = 1215.
  • 33% was mislabeled or misidentified, hence p = 0.33.
  • 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

<h3>The lower limit of this interval is:</h3>

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.33 - 1.96\sqrt{\frac{0.33(0.67)}{1215}} = 0.3036

<h3>The upper limit of this interval is:</h3>

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.33 + 1.96\sqrt{\frac{0.33(0.67)}{1215}} = 0.3564

The 95% confidence interval for the proportion of all seafood sold in the United States that is mislabeled or misidentified is (0.3036, 0.3564).

You can learn more about the use of the z-distribution to build a confidence interval at brainly.com/question/25730047

4 0
2 years ago
Eureka math 7th grade module 1: Complex fractions. Can someone explain complex fractions to me???
Softa [21]
It is where the numerator and the denominator (or both) contain a fraction. 
7 0
3 years ago
Three numbers have a median of 7, a range of 7 and a total of 16. Give the three numbers.
Lemur [1.5K]

Answer:

The numbers would have to be 7, 8 and 1.

Step-by-step explanation:

To find this, first note that 7 needs to be the middle number. So one will be greater and one smaller.

Next we know that the last two numbers must add up to 9. This is because after we subtract 7 from the total, we get 9.

Now since they need to equal 9 and be 7 apart, we can find that 8 and 1 are the only numbers that satisfy that stipulation.

6 0
4 years ago
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