All categories

2 years ago

The length of a rectangle is three times its width the length is 3 3/4 feet. What is the area if the rectangle?

Mathematics

1 answer:

Roman55 [17]2 years ago

4 0

Answer:

A = 4 11/16 or 4.6875

Step-by-step explanation:

3 3/4 = 3W

divide both sides by 3

15/4 divided by 3 = W

15/4 x 1/3 = W

5/4 = W

A = L x W

3 3/4 x 1 1/4 = 15/4 x 5/4 = 75/16 = 4 11/16

You might be interested in

If two sides of one triangle are proportional to two sides of another and included angles are equal, then the triangles are simi

tiny-mole [99]

Yes the triangles are similar. It’s true

8 0

2 years ago

The stack on the left is made up of 15 pennies, and the stack on the right is also made up of 15 pennies. If the volume of the s

Svetlanka [38]

Answer:

i am not good in maths sorry the answer is 6075

3 0

2 years ago

How do you use the exchange rate to calculate the amount of ARS that is equal to 350 AUD

Anna11 [10]

Your answer would be 6678.02

7 0

3 years ago

Find y when x = 3 of the equation for y=2x+12

ser-zykov [4K]

Answer:

y = 18

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

y = 2x + 12

x = 3

Step 2: Evaluate

Substitute in x: y = 2(3) + 12
Multiply: y = 6 + 12
Add: y = 18

3 0

2 years ago

Read 2 more answers

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$

At t = 0

$C(0) = 8(e^{(0)}-e^{(0)}) = 0$

At t = 2

$C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185$

At t = 12

$C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059$

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

4 0

2 years ago