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larisa [96]
3 years ago
8

How is multiplying exponents (x^2*x^4) different from raising a power to a power((x^2)^4)? Ty =)

Mathematics
1 answer:
Contact [7]3 years ago
8 0

Answer:

When your multiplying exponents in the same parenthasis like x^2*x^4, you'll add the exponents so it will be x^6. If it is outside the parenthasis like (x^2)^4 you'll multiply the exponents so it will be x^8. good luck! :)

Step-by-step explanation:

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You need a new mat to place under your dogs water bowl. The mat has a diameter of 24 inches and the water bowl has a diameter of
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Answer:

200.96

Step-by-step explanation:

So, we have to find the area of both.

The area for the mat is

(pi)12^2=3.14x144. However, since it is HALF a circle, we divide it by two.

So, 226.08

Next, the water bowl.

(3.14)4^2=50.24.

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I may be wrong!

7 0
2 years ago
When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
3 years ago
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kipiarov [429]
\bold{ANSWER:}
$8725

\bold{EXPLANATIONS:}

4 0
2 years ago
Solve for X <br><br> Will give brainiest
o-na [289]

Answer:

x = 6

Step-by-step explanation:

8x + 2 + 70 + 60 = 180

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7 0
3 years ago
10^-3<br> it told me i needed to write more characters
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try .01

Step-by-step explanation:

3 0
2 years ago
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