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3 years ago

How is multiplying exponents (x^2*x^4) different from raising a power to a power((x^2)^4)? Ty =)

Mathematics

1 answer:

Contact [7]3 years ago

8 0

Answer:

When your multiplying exponents in the same parenthasis like x^2*x^4, you'll add the exponents so it will be x^6. If it is outside the parenthasis like (x^2)^4 you'll multiply the exponents so it will be x^8. good luck! :)

Step-by-step explanation:

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What is 3 1/8 - 1 7/8=

photoshop1234 [79]

Answer:

1 1/4

Step-by-step explanation:

3 1/8 - 1 7/8

I like to line them up vertically

3 1/8

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We need to borrow from the 3

Take 1 from the 3 and make it 8/8

2 (1/8+8/8)

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2 (9/8)

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Simplify the fraction by dividing by 2 on the top and bottom

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3 years ago

Solve using long division <br> Please

madreJ [45]

1. $Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}$

$Steps:$

$\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}$

$\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}$

$\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}$

$\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}$

$\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}$

2. $Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}$

$Steps:$

$\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}$

$\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}$

$\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

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3 years ago

How many pots can nestor plan in 1 hour if he plants 15 plants in 2.5 hours

Flauer [41]

He can plant 6 pots in 1 hr

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3 years ago

i dontusually like math so this is probablly easy for you, what is pie multiplied by 6, and divided to the fourth

Nezavi [6.7K]

<span>π </span>* 6 = 18.8495559215 / 4 = 4.71238898038

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3 years ago

A plumber uses the expression 48 + 25h to determine the number of dollars to change each customer. If H = 4 how much does the cu

Oliga [24]

If H = 4, we simply plug 4 into the position of h in the expression.

48 + 25 * 4

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148

The customer pays $148

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3 years ago

Read 2 more answers