Answer:
The c++ program for the given scenario is given below.
#include <iostream>
using namespace std;
int main() {
double galleons, knuts;
cout << " This program converts Galleons to Knuts " << endl;
cout << " Enter the number of galleons to be converted into knuts: " << endl;
cin >> galleons;
knuts = galleons * 493;
cout << galleons << " Galleons is equivalent to " << knuts << " Knuts. " << endl;
return 0;
}
OUTPUT
For decimal value.
This program converts Galleons to Knuts
Enter the number of galleons to be converted into knuts:
1.1
1.1 Galleons is equivalent to 542.3 Knuts.
For integer value.
This program converts Galleons to Knuts
Enter the number of galleons to be converted into knuts:
2
2 Galleons is equivalent to 986 Knuts.
Explanation:
This program uses two variables to holds galleons and knuts which are declared with data type double.
double galleons, knuts;
The data type double is taken since it can hold both integer and decimal values.
The variables are not initialized since the program is supposed to take user input for the number of galleons to be converted to knuts as shown below.
The cout keyword is used to print to the standard output.
cout << " Enter the number of galleons to be converted into knuts: " << endl;
The cin keyword is used to take the input from the user.
cin >> galleons;
Galleons are converted into knuts using the conversion rate given in the question. The formula to convert galleons into knuts is given as follows.
knuts = galleons * 493;
The entered number of galleons and the corresponding number of knuts are displayed to the standard output.
cout << galleons << " Galleons is equivalent to " << knuts << " Knuts. " << endl;
In the program, endl keyword is used to insert new line.
The program terminates with the following statement since the return type of main is shown as integer.
return 0;
