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vesna_86 [32]
2 years ago
5

The current annual interest rate is 5 percent, and you are taking out a 20-year loan with a monthly end-of-month payment. If you

can afford monthly payments of $3000 per month, what is the most you can borrow?
Computers and Technology
1 answer:
arlik [135]2 years ago
7 0

Answer:

720k.

Explanation:

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A program is required to three (3) numbers. calculate and print their total
podryga [215]

A program that is required to three (3) numbers. calculate and print their total is given below:

<h3>The Program</h3>

import java.util.Scanner;

public class SumAndAverage {

public static void main(String[ ] args) {

System.out.println("Enter three numbers - ");

// Accepting and finding sum of numbers.

int sum = 0;

Scanner sc = new Scanner(System.in);

for (int i = 0; i < 3; i++)

sum += sc.nextInt( );

// Printing sum and average.

System.out.println("Sum - " + sum);

System.out.println("Average - " + (sum / 3f));

}

}

The output would request three different numbers, then add them up, and display the output of the sum and then display or print their total


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5 0
2 years ago
Given a String variable named sentence that has been initialized, write an expression whose value is the number of characters in
Troyanec [42]
Python:

sentence = “this is the sentence.”
size = len(sentence)

C++:

string sentence = “this is the sentence.”
int size = sentence.size()

* Remember strings are just arrays of characters.

5 0
3 years ago
Choose the appropriate software category for each specific application shown.
Tom [10]
Python is the correct answer
7 0
2 years ago
How does the technology work
Ivan

Answer:  it does – or perhaps appears to do – in the world.

Explanation:

sorry if am not right have a nice day lol

6 0
3 years ago
Read 2 more answers
The variable 'a' starts with the value 1 The variable 'b' starts with the value 10 The variable 'c' starts with the value 100 Th
Anettt [7]

Answer:

The answer is B = 365

Explanation:

The following variable were initialized:

a = 1

b = 10

c = 100

x = 0

Then we store the value of 'c' times 3 in 'x'

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x = 300

Then we add the value of 'b' times 6 to the value already in 'x'

x = x + 'b' times 6

x = x + (b * 6) = 300 + (10 * 6) = 300 + 60 = 360

x = 360

Then we add the value of 'a' times 5 to the value already in 'x'

x = x + 'a' times 5

x = x + (a * 5) = 360 + (1 * 5) = 360 + 5 = 365

x = 365.

Therefore, the value of 'x' displayed is 365.

4 0
4 years ago
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