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Law Incorporation [45]
3 years ago
15

Find the arc length of the semicircle. 8

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

π×8² =

201.0619298297

arc length formular = π ×r²

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The mass of a an atom of helium is 6.65 x 10^−24. Use scientific notation to express the mass of 250 helium atoms.
melisa1 [442]
<span>1.6625 x 10−21</span>

<span>mass of one helium atom x 250 </span>
Express 250 as 2.50.
(6.65 x 10−24)(2.50 x 102)
16.625 x 10<span>−22</span>
5 0
3 years ago
Read 2 more answers
Show problem set up for full credit.
ICE Princess25 [194]

Answer:

∠ QPR = 125°

Step-by-step explanation:

the angles subtended by 2 congruent arcs are congruent , that is

5x = 4x + 25 ( subtract 4x from both sides )

x = 25

Then

∠ QPR = 4x + 25 = 4(25) + 25 = 100 + 25 = 125°

5 0
2 years ago
The cost of a concert ticket last week was $50.00. This week a concert ticket is $55.00. The percent increase of the ticket from
marta [7]

Answer:

110% pls give brainliest

Step-by-step explanation:

4 0
2 years ago
An electrical engineer wishes to compare the mean lifetimes of two types of transistors in an application involving high-tempera
Olin [163]

Answer:

(115.2642, 222.7358).

Step-by-step explanation:

Given data:

type A: n_1=60, xbar_1=1827, s_1=168

type B: n_2=180, xbar_2=1658, s_2=225

n_1 = sample size 1, n_2= sample size 2

xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.

a=0.05, |Z(0.025)|=1.96 (from the  standard normal table)

So 95% CI is

(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]

=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)

= (115.2642, 222.7358).

8 0
3 years ago
Pls help me out with this:
djyliett [7]

1. 20 x 8 = 160 m

2.

January to November = 11 months.

11 flats are painted every year.

100 flats / 11 flats per year = 9 years + 1 month 

the next time it will be painted is September 2019.

7 0
3 years ago
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