Answer:
6.0 square feet
Step-by-step explanation:
6 ÷ 2 = 3(radius)
are of the damaged section = x
77/360 = x/3²π
=> x = 77 × 9π ÷ 360 = 6.0445 <= 6.0 square feet is the closest to this number
<u>x₁ + x₂</u> <u>y</u>₁ + <u>y</u>₂<u>
</u> 2 = M 2 = M
<u>
x + 8</u> <u>y + -2</u><u>
</u> 2 = -4 2 =6
<u>multiply both sides by 2.
</u>x+8=-8 y - 2 = 12
<u>x = -16</u> <u>y = 14
</u>
Final Answer: (-16, 14)
Answer:
10:12
Step-by-step explanation:
hope it helped!!
xxx me!
See the attached picture.
<span>you are given that ABCE is an isosceles trapezoid. </span>
<span>you are given that AB is parallel to EC. </span>
<span>this means that AE is congruent to BC. </span>
<span>you are given that AE and AD are congruent. </span>
<span>triangle EAD is an isosceles triangle because AE and AD are congruent. </span>
<span>this means that angle 1 is equal to angle 3. </span>
<span>since angle 1 is equal to angle 2 and angle 3 is equal to angle 1, then angle 3 is also equal to angle 2. </span>
<span>this means that AD and BC are parellel because their corresponding angles (angles 3 and 2) are equal. </span>
<span>since AB is parallel to EC and DC is part of the same line, than AB is parallel to DC. </span>
<span>you have AB parallel to DC and AD parallel to BC. </span>
<span>if opposite sides of a quadrilateral are parallel, then the quadrilateral is a parallelogram. </span>
<span>that might be able to do it,depending on whether all these statements are acceptable without proof. </span>
<span>they are either postulates or theorems that have been previously proven. </span>
<span>if not, then you need to go a little deeper and prove some of the statements that you used.. </span>
here's my diagram.
<span>this is not a formal proof, but should give you some ideas about how to proceed. </span>
<span>you can also prove that angle 4 is equal to angle 2 because they are alternate interior angles of parallel lines. </span>
<span>you can also prove that angle 6 is equal to angle 5 because they are alternate interior angles of parallel lines. </span>
