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Vsevolod [243]
3 years ago
11

According to the Big Five Factors model, all but _____ are categories.

Computers and Technology
2 answers:
Marat540 [252]3 years ago
8 0
Hey You!

The Five traits are:

• Extraversion.

• Agreeableness.

• Conscientiousness.

• Neuroticism.

• Openness.

So, all but Empathetic are categories.
nika2105 [10]3 years ago
5 0
<span>According to the Big Five Factors model, all but OPENNESS are categories. </span>
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which server edition doesn't support any server roles that you would typically use with standard version
ioda

On the standard version of Microsoft Windows, Dynamic Host Configuration Protocol Server and Hyper-V Remote Access are two roles that aren't supported on Azure Virtual Machines - a type of server.

<h3>What is a Server?</h3>

It is to be noted that this is a computer device (hardware) or virtual environment (software) that feeds another computer with special services.

<h3>Type of Server</h3>

The following are various types of servers:

  • Webserver
  • Proxy Server
  • Virtual Machine (VM)
  • Database Server
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See the link below for more about Servers:

brainly.com/question/25435769

8 0
3 years ago
Computers are said to use binary data because all computer data is simply a series of Os and 1s.
Bingel [31]

Answer:

True

Explanation:

The option that answers the question is "True" and this is due to the fact that computers and computing devices represent data using 0s and 1s .

Although, the users of the computer do not have to study binary digits before they are able to interact with the computer, the computer itself can not function without binary digits.

So, for every input you pass to the computer, a translator translates it to binary for the computer to understand your input.

Hence, the statement in the question is true.

7 0
3 years ago
Problem 1: you must write a method for this problem called sentenceAnalyzer Write a program that reads a sentence from the keybo
forsale [732]

Answer:

   static void sentenceAnalyzer(String sentence){

       int lenOfString = sentence.length()-1;

   

           if(sentence.charAt(lenOfString)=='.'){

               System.out.println("Declarative");

             

           }

           else   if(sentence.charAt(lenOfString)=='?'){

               System.out.println("Interrogative");

             

           }

           else if(sentence.charAt(lenOfString)=='!'){

               System.out.println("Exclamation");

             

           }

           else{

               System.out.println("Unknown");

             

           }

   

   }

Explanation:

Using Java programming language

Create the method as required

Obtain the index of the last element using the string length method

Use if and else statements to check if the character at the last index is equal to any of the characters given and print the expected output

see a complete code with the main method below

<em>import java.util.Scanner;</em>

<em>public class num11 {</em>

<em>    public static void main(String[] args) {</em>

<em>        Scanner in = new Scanner(System.in);</em>

<em>        //Receiving User input</em>

<em>        System.out.println("Enter a sentence");</em>

<em>        String sentence = in.nextLine();</em>

<em>        // Calling the method</em>

<em>        sentenceAnalyzer(sentence);</em>

<em>    }</em>

<em>    static void sentenceAnalyzer(String sentence){</em>

<em>        int lenOfString = sentence.length()-1;</em>

<em />

<em>            if(sentence.charAt(lenOfString)=='.'){</em>

<em>                System.out.println("Declarative");</em>

<em>            }</em>

<em>            else   if(sentence.charAt(lenOfString)=='?'){</em>

<em>                System.out.println("Interrogative");</em>

<em>            }</em>

<em>            else if(sentence.charAt(lenOfString)=='!'){</em>

<em>                System.out.println("Exclamation");</em>

<em>            }</em>

<em>            else{</em>

<em>                System.out.println("Unknown");</em>

<em>            }</em>

<em>    }</em>

<em>}</em>

<em />

8 0
3 years ago
An IT suspects that an unauthorized device is connected to a wireless network. This is a result of pastry sharing on a device br
telo118 [61]

Answer:

3. WiFi Protected Access 2

Explanation:

Given that Wi-Fi Protected Access 2 often referred to as WAP 2 is a form of computer security or privacy measure to ensure that Wireless networks are furnished with powerful security of data network access control.

Hence, when a user employed or utilize WPA2. It gives such a user a high degree of maximum certainty of controlling the users that can have access to his wireless network.

Hence, in this case, what is put in place to stop such activity is Wi-Fi Protected Access 2

6 0
3 years ago
Timeliness is an important goal of any access control monitoring system.<br> A. True<br> B. False
Damm [24]
The answer for this question is true
7 0
4 years ago
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