If the temperature at 1:00 is x, then Jonestown's temperature at 3:00 is
x-10-8 (since it dropped 10 degrees then 8 more degrees)=x-18
Using x for Cooperville too, we get x-6-2 (since it drops 6 degrees then 2 more degrees) = x-8
Since -8 is greater than -18, Cooperville's temperature is warmer and Jonestown's temperature is lower aka colder<span />
The equation of a circle is:
(x-h)^2 + (y-k)^2 = r^2
where (h,k) is the location of the center and r is the radius. So we need to find h, k, and r. The center is given as (5,-4) so h = 5 and k = -4:
(x-5)^2 + (y-(-4))^2 = r^2
(x-5)^2 + (y+4)^2 = r^2
So we need to find r. Use the distance formula to find the distance between (5,-4) and (-3,2):
r = [(5-(-3))^2+((-4)-2)^2]^1/2
r = [8^2 + (-6)^2]^1/2
r = [64 + 36]^1/2
r = 100^1/2
r= 10
The final equation is:
(x-5)^2 + (y+4)^2 = 10^2
Answer:
Width
Step-by-step explanation:
When we have quantitative data it is grouped in classes. There are three ways in which the data can be grouped they are:
Single value grouping where each class has one distinct value.
In Cutpoint grouping is used when the observations have decimal points
In Limit grouping a classes are set based on a specified range of values. Here limit grouping is being done and the range of each class is called width.
Answer:
Mother's Present Age = 36 years
Daughter's Present Age = 12 years
Step-by-step explanation:
Let present age of mother be "m" and present age of daughter be "d"
Mother is 24 years older than her daughter, so we can write:
m = 24 + d
8 years ago, Mother was 7 times old as daughter, that would be:
m - 8 = 7(d - 8)
Note, since 8 years ago, both "m" and "d" have 8 subtracted from it.
Now we substitute Equation 1 into Equation 2 and solve for d:
Mother age, m, would be:
m = 24 + d
m = 24 + 12
m = 36
Hence,
Mother's Present Age = 36 years
Daughter's Present Age = 12 years
