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Alchen [17]
3 years ago
15

Arnie is mixing red and yellow paints to make two different shades of orange. To make 1 cup of dark orange​ paint, he needs 7 ou

nces of red paint and 1 ounce of yellow paint. To make 2 cups of light orange​ paint, he needs 13 ounces of yellow paint and 3 ounces of red paint. Answer parts a and b.
a. Arnie buys a​ 32-oz can of red paint. Does he have enough red paint to make 3 cups of dark orange paint and 3 cups of light orange​ paint? Explain.
Yes.
The 3 cups of dark orange paint require
21
21 ​ounce(s) of red​ paint, and the 3 cups of light orange paint require
9
4.5 ​ounce(s) of red paint. Arnie needs
30
25.5 ​ounce(s) of red paint in​ total, so the​ 32-oz can is
enough.
​(Type integers or​ decimals.)
b. Arnie decides to make 3 cups of dark orange paint and 3 cups of light orange paint. How many ounces of yellow paint does he​ need?
Arnie needs
4216
nothing ​ounce(s) of yellow paint. The 3 cups of dark orange require
3
3 ​ounce(s) of yellow​ paint, and the 3 cups of light orange require
391313
nothing ​ounce(s) of yellow paint.
​(Type integers or​ decimals.)
Mathematics
1 answer:
katrin2010 [14]3 years ago
7 0

Answer:

Integers and decimals

Step-by-step explanation:

Soorry im too lazy to read all this

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45ci

Step-by-step explanation:

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5 0
2 years ago
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1. Identify a pair of alternate exterior angles.
alisha [4.7K]
First answer is the fourth one, 2 and 6
3 0
3 years ago
Which choices are equivalent to the expression below? Check all that apply. 6√3
Westkost [7]

Answer:

case A. \sqrt{18}*\sqrt{6}

case B. \sqrt{108}

case E. \sqrt{3}*\sqrt{36}

Step-by-step explanation:

we have

6\sqrt{3}

we know that

6\sqrt{3}=\sqrt{36*3}=\sqrt{108}

<u>Verify each case</u>

case A) \sqrt{18}*\sqrt{6}

\sqrt{18}*\sqrt{6}=\sqrt{18*6}=\sqrt{108}

therefore

\sqrt{18}*\sqrt{6} is equivalent to 6\sqrt{3}

case B) \sqrt{108}

so

\sqrt{108} is equivalent to 6\sqrt{3}

case C) \sqrt{3}*\sqrt{6}

\sqrt{3}*\sqrt{6}=\sqrt{18}

therefore

\sqrt{18} is not equivalent to 6\sqrt{3}

case D) \sqrt{54}

so

\sqrt{54} is not equivalent to 6\sqrt{3}

case E) \sqrt{3}*\sqrt{36}

\sqrt{3}*\sqrt{36}=\sqrt{108}

therefore

\sqrt{3}*\sqrt{36} is equivalent to 6\sqrt{3}

case F) 108

so

108 is not equivalent to 6\sqrt{3}

6 0
2 years ago
Is this right I need help with this
Margarita [4]
Y axis is counting by 2's
it started at 2 and went up to 6
Y = 4

X axis is counting by 2'2
starts at one goes to 3
X = 2

Slope is 4/2 because rise over run
4/2 = 2
Slope is simplified to 2. 
5 0
3 years ago
Mary has a collection of nickels and quarters for a total of $4.90. If she has 42 coins in total, how many of each kind are ther
damaskus [11]

Answer:

14 quarters and 28 nickels

Step-by-step explanation:

System of Equations where x = number of quarters and y = number of nickels

(1) equation with value of each coin

    0.25(x)+0.05(y) = 4.90

(2) total number of coins

    x + y = 42

Solve system of equations using either substitution or elimination

(elimination multiplying equation 2 by -0.5)

.25(x) + 0.05(y) = 4.90

-0.05(x) - 0.05(y) = 42 * (-0.05)

(3) Resulting equation

.20(x) = 2.8

x = 14

plug x into equation 2

14 + y = 42

y = 28

There are 14 quarters and 28 nickels in Mary's collection.

5 0
3 years ago
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