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Dahasolnce [82]
3 years ago
9

Dallas wants to know what elective subjects the students like the best. He surveys students who are leaving band class. is this

a random sample or a biased sample and why
Mathematics
2 answers:
valentina_108 [34]3 years ago
4 0
Biased because band is an elective.

AlladinOne [14]3 years ago
3 0
Biased since hes just asking band stuents and they are likely to answer that and is the best, to conducts an unbiased survey he should ask random kids in the courtyard or every kid that walks through the office
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Find the Mean Absolute Deviation of the set: 48, 52, 54, 61, 30, 76, 77,50
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In parallelogram ABCD, the measure of angle A = 3x and the measure of angle B = x + 10.
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Answer: 42.5

Step-by-step explanation:

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Is this angle complementary or supplementary or neither?
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Neither

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Theoretical Probability - Guided Practice#1 - All of the letters in the word Mississippi are written on separate pieces of paper
Naily [24]

The probability = outcome/total outcomes

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\begin{gathered} P(s)=\frac{4}{11}\times100 \\ P(s)=36.4 \end{gathered}

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Answer C

5 0
1 year ago
Use the laplace transform to solve the given initial-value problem. y' 5y = e4t, y(0) = 2
Basile [38]

The Laplace transform of the given initial-value problem

y' 5y = e^{4t}, y(0) = 2 is  mathematically given as

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>

Generally, the equation for the problem is  mathematically given as

&\text { Sol:- } \quad y^{\prime}+s y=e^{4 t}, y(0)=2 \\\\&\text { Taking Laplace transform of (1) } \\\\&\quad L\left[y^{\prime}+5 y\right]=\left[\left[e^{4 t}\right]\right. \\\\&\Rightarrow \quad L\left[y^{\prime}\right]+5 L[y]=\frac{1}{s-4} \\\\&\Rightarrow \quad s y(s)-y(0)+5 y(s)=\frac{1}{s-4} \\\\&\Rightarrow \quad(s+5) y(s)=\frac{1}{s-4}+2 \\\\&\Rightarrow \quad y(s)=\frac{1}{s+5}\left[\frac{1}{s-4}+2\right]=\frac{2 s-7}{(s+5)(s-4)}\end{aligned}

\begin{aligned}&\text { Let } \frac{2 s-7}{(s+5)(s-4)}=\frac{a_{0}}{s-4}+\frac{a_{1}}{s+5} \\&\Rightarrow 2 s-7=a_{0}(s+s)+a_{1}(s-4)\end{aligned}

put $s=-s \Rightarrow a_{1}=\frac{17}{9}$

\begin{aligned}\text { put } s &=4 \Rightarrow a_{0}=\frac{1}{9} \\\Rightarrow \quad y(s) &=\frac{1}{9(s-4)}+\frac{17}{9(s+s)}\end{aligned}

In conclusion, Taking inverse Laplace tranoform

L^{-1}[y(s)]=\frac{1}{9} L^{-1}\left[\frac{1}{s-4}\right]+\frac{17}{9} L^{-1}\left[\frac{1}{s+5}\right]$ \\\\

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

Read more about Laplace tranoform

brainly.com/question/14487937

#SPJ4

6 0
2 years ago
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