Your question is somewhat ambiguous.
If you want to solve this equation for y in terms of x, first multiply all of its terms by the LCD (which is 5), to remove the fractions.
5(3/5)x + 5(1.4y) = 5(2/5)
Then 3x + 7y = 2 This is the equation of the line in "standard form."
Next, subtract 3x from both sides: 7y = -3x + 2
Dividing by 7, y = (-3/7)x + (2/7)
This is the slope-intercept form of the given equation. It has a slope of -3/7 and a y-intercept of (0, 2/7).
The point-slope form of the same equation is
y- 2/7 = (-3/7)(x - 0), or -3x/7. y - 2/7 = (-3/7)x
Answer:
Henry still has to mow 75% of the laws.
Step-by-step explanation:
It is given that Henry has 15 lawns mowed out of a total of 60 lawns.
We need to find: What percent of the lawns do Henry still have to mow?
Henry has 60 lawns in total.
He mowed 15 out of them.
The percentage of lawns mow = ![\frac{15}{60} \times 100=25 \%](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B60%7D%20%5Ctimes%20100%3D25%20%5C%25)
Henry mowed 25% of total lawns.
The percent of laws still have to mow = 100%-25%
The percent of laws still have to mow = 75%
Hence, Henry still has to mow 75% of the laws.
The answer of this is 6 flags at 8 are rousters that are very loud x+6 description chicken x-9 plus a side of gravy and cheese x-9 x+6 d
Need more information but Henry would make an 85% on his test.
The percent error in the meteorologist's forecast for Monday is 5.26316 %
<h3><u>
Solution:</u></h3>
Given that Monday's high temperature would be 76°F
On Monday, the temperature reached 80°F
To find: percent error in the meteorologist's forecast for Monday
Percent error is the difference between a measured and known value, divided by the known value, multiplied by 100%
<em><u>The percent error is given as:</u></em>
![\text {percent error }=\frac{\text {observed - standard}}{\text { standard value}} \times 100](https://tex.z-dn.net/?f=%5Ctext%20%7Bpercent%20error%20%7D%3D%5Cfrac%7B%5Ctext%20%7Bobserved%20-%20standard%7D%7D%7B%5Ctext%20%7B%20standard%20value%7D%7D%20%5Ctimes%20100)
Here standard value = 76 and observed value on monday = 80
![\text { percent error }=\frac{80-76}{76} \times 100](https://tex.z-dn.net/?f=%5Ctext%20%7B%20percent%20error%20%7D%3D%5Cfrac%7B80-76%7D%7B76%7D%20%5Ctimes%20100)
![\text { percent error }=\frac{4}{76} \times 100=5.26316 \%](https://tex.z-dn.net/?f=%5Ctext%20%7B%20percent%20error%20%7D%3D%5Cfrac%7B4%7D%7B76%7D%20%5Ctimes%20100%3D5.26316%20%5C%25)
Thus percent error in the meteorologist's forecast for Monday is 5.26316 %