The square of the diagonal (d1) of the end face is
.. (d1)^2 = (3 in)^2 +(5 in)^2 = (9 +25) in^2 = 34 in^2
The square of the longest diagonal (d2) will be given by
.. (d2)^2 = (3x in)^2 +(d1)^2
.. = (9x^2 +34) in^2
So, the longest diagonal is
.. d2 = √(9x^2 +34) in
Answer:<em><u> x= 4/3 but in decimal form =1.333</u></em>
Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
4-(2*(3*x-2))=0
4 - 2 • (3x - 2) = 0
Pull out like factors :
8 - 6x = -2 • (3x - 4)
Solve : 3x-4 = 0
Add 4 to both sides of the equation :
3x = 4
Divide both sides of the equation by 3:
<em><u>x = 4/3 = 1.333</u></em>
What question sir i’m willing to help:)
Answer:
jdjndbncjjsnnxjjxjnxjnsnnx.
DA/dx = 36cos2x by chain rule.
