Answer:
1. y = (⅔)x - 3
2. y = 3x + c
3. 1) non-proportional
2) can be proportional if c = 0
Step-by-step explanation:
1. What is the equation of a line that has a slope of ⅔ and a y-intercept of -3?
y = (⅔)x - 3
2. What is the equation of a line that has a slope of 3?
y = 3x + c
3. Lable the 2 equations as proportional or non-proportional and why.
A proportional relation should pass through the origin, i.e the y-intercept should be 0
right-handThe triangles are similar if, the ratios of their sides are equal
![\frac{AE}{AC}=\frac{AW}{AL}](https://tex.z-dn.net/?f=%5Cfrac%7BAE%7D%7BAC%7D%3D%5Cfrac%7BAW%7D%7BAL%7D)
![\frac{8+8}{6+6}=\frac{8}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B8%2B8%7D%7B6%2B6%7D%3D%5Cfrac%7B8%7D%7B6%7D)
On the left-hand side
![\frac{16}{12}=\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7B12%7D%3D%5Cfrac%7B4%7D%7B3%7D)
and in the right-hand side, we have
![\frac{8}{6}=\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B6%7D%3D%5Cfrac%7B4%7D%7B3%7D)
The left-hand side equals the right-hand side; therefore, the triangles are similar.
Step-by-step explanation:
-3x-9
divide the equation by -1 so that the -1's are taken from -3x and -9. so the -1 goes on the outside of 3x+9
-1(3x+9)
then divide the equation by 3 since 3x and 9 is divisible by 3.
(-1)(3)(3/3x+9/3)
-3(x+3)
Now we can expand again to check the problem
-3 times x=-3x
-3 times 3=-9
and add
-3x-9
Hope that helps :)
It will move it from one section to another and make the x axis 4 units more to the right