Question

In a genetics experiment on​ peas, one sample of offspring contained 450 green peas and 371 yellow peas. Based on those​ results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of three fourths that was​ expected?

Answer 1

Answer:

P(G) = 0.55

the probability of getting an offspring pea that is green. Is 0.55.

Is the result reasonably close to the value of three fourths that was​ expected?

No

Expected P(G)= three fourths = 3/4 = 0.75

Estimated P(G) = 0.55

Estimated P(G) is not reasonably close to 0.75

Step-by-step explanation:

Given;

Number of green peas offspring

G = 450

Number of yellow peas offspring

Y = 371

Total number of peas offspring

T = 450+371 = 821

the probability of getting an offspring pea that is green is;

P(G) = Number of green peas offspring/Total number of peas offspring

P(G) = G/T

Substituting the values;

P(G) = 450/821

P(G) = 0.548112058465

P(G) = 0.55

the probability of getting an offspring pea that is green. Is 0.55.

Is the result reasonably close to the value of three fourths that was​ expected?

No

Expected P(G)= three fourths = 3/4 = 0.75

Estimated P(G) = 0.55

Estimated P(G) is not reasonably close to 0.75