Answer: Cut the stem and if the vascular bundles are scattered in the stem, it is a monocot.
Explanation:
The plant is whether monocot or dicot can be identified by the cross-section of the stem if leaves, flowers, fruits or seeds are not available.
In the cross-section of the monocot stem, the vascular bundles are scattered, without following a definite arrangement, whereas the dicot stem, will have the vascular bundles that have a definite shape, aligned in the form of rings.
In the case of monocot stem the bundle sheath is present whereas in case of dicot stem the bundle sheet is absent.
❅ First to <span>classify all living beings.
❅ As well to record all living plants during his time.
</span>
Answer:
The proportion of the genotypic recombinants among the offspring from this cross is 75%
Explanation:
Separating the alleles from the parents independently, We have AB, Ab, aB, and ab.
These should be crossed using punnet's square, we will therefore get the genotypic of the 16 progenies as: AABB, AABb, AaBB, AABb, AAbb, AaBb, AaBB, AaBb, aaBB, AaBb, Aabb, aaBb, aabb, aaBb, Aaaa and AaBb. From these, only those in bold retained the genotype of their heterozygous parents. Therefore, 12 out of 16 are genetic recombinant, which are the offspring that differs from their parents after a cross. This made the proportion to be 12/16 X 100 = 75%.
Answer:
XDxd
Explanation:
the recessive allele for the disease is represented by (d).
the dominant allele for not having the disease is represented by (D)
in order to not be affected, we know that the mother must have one uppercase D, so the last option is wrong. And in order to pass it on to her child, she needs one lower case d (to give to the child). So the second answer is correct. good luck :).