Answer:
4.72 hours/day
Step-by-step explanation:
Mean time spent watching TV (μ) = 2.8 hours a day
Standard deviation (σ) = 1.5 hours a day
The 90th percentile (upper 10%) of a normal distribution has an equivalent z-score of roughly z = 1.282. The minimum time spent watching TV, X, at the 90th percentile is:
On a typical day, you must watch at least 4.72 hours of TV to be in the upper 10%.
If you put 7% into a decimal it would be 0.07
for 10 x = 28.
8x-44=180
+44. +44
8x=224
224/8=28
Answer:
P(E|F)=60% P(E)=60% Events E and F are independent
Step-by-step explanation:
I took it and got it right
Answer:
Step-by-step explanation:
1. Find the GCD ( or HCF) of numerator and denominator
<u>GCD of 5 and 14 is 1</u>
2. Divide both the numerator and denominator by the GCD
5 divide 1 and 14 divide 1
3 reduced fraction
5/14
