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Oksi-84 [34.3K]
3 years ago
8

Please help will mark as brainless

Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

Answer:

1.  r =  \sqrt[3]{\frac{3v}{4\pi } }

divide v by 4/3, this is the same as multiplying v by 3/4 so you have 3v/4

then divide v by \pi so you now have 3v/4\pi

then get rid of the ^3 on r by putting the solution for r under a ∛

2. a) The equation might need to be written in terms of a because you may not know the value of a, but you know the value of everything else. If this is the case then you can simply rewrite the equation so that you can plug it all into a calculator and avoid certain possible errors.

     b)

 s = ut + 1/2 at^{2}

subtract ut from both sides: s - ut = 1/2 at^{2}

multiply both sides by 2: 2(s - ut)

divide both sides by t^{2}: \frac{2(s - ut) }{t^{2} } = a

answer: a =  \frac{2(s - ut) }{t^{2} }

I'm not entirely sure about b) for question 2 so you might wanna double check that with a friend

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If y = 10x - 1 and the value of x is 10, what is the value of y?
KatRina [158]

Answer:

99

Step-by-step explanation:

99 because x= 10 so 10 times 10 is 100 - 1 will = 99

5 0
3 years ago
Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

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Sav [38]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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