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Oksi-84 [34.3K]
3 years ago
8

Please help will mark as brainless

Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

Answer:

1.  r =  \sqrt[3]{\frac{3v}{4\pi } }

divide v by 4/3, this is the same as multiplying v by 3/4 so you have 3v/4

then divide v by \pi so you now have 3v/4\pi

then get rid of the ^3 on r by putting the solution for r under a ∛

2. a) The equation might need to be written in terms of a because you may not know the value of a, but you know the value of everything else. If this is the case then you can simply rewrite the equation so that you can plug it all into a calculator and avoid certain possible errors.

     b)

 s = ut + 1/2 at^{2}

subtract ut from both sides: s - ut = 1/2 at^{2}

multiply both sides by 2: 2(s - ut)

divide both sides by t^{2}: \frac{2(s - ut) }{t^{2} } = a

answer: a =  \frac{2(s - ut) }{t^{2} }

I'm not entirely sure about b) for question 2 so you might wanna double check that with a friend

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natta225 [31]

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4 0
3 years ago
NEED HELP ASAP !!!!!!!!
Papessa [141]

Answer: Stephon can buy total 4 chips bag and 2 candy bar

Step-by-step explanation:Given as :

The money which Stephon has in his pocket = $ 12

The cost of one chips bag = $ 2.25

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The total number of items he can buy = 6

So, Let the number of chips bag he can buy = x

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Now, according to question

The number of chips bag×The cost of one chips bag + The number of candy bar×The cost of one candy bar = $ 12

Or, x × $ 2.25 + (6-x) × $ 1.50 = $ 12

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or,  x × $ 0.75 = 12 - 9

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The number of chips bag he can buy = x = 4

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4 0
3 years ago
What is the area of this figure?
Elanso [62]
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Similarly, the area of a triangle is one half times base times height, so At=( \frac{1}{2})bh. Since we know that our base is 8cm and our height 6cm, lets replace those values in our equation to find the area of our triangle:
A_{t} =( \frac{1}{2})(8cm)(6cm)
A_{t} =24cm^{2}

Now the only thing left is add our areas:
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3 years ago
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The equation for the horizontal line is
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