private static String removeFromString(String old, String frag)
{
int i = old.indexOf(frag);
while (i> -1) {
String rest = old.substring(i + frag.length());
System.out.println("rest = " + rest);
old = old.substring(0, i);
System.out.println("rest = " + old);
old = old + rest;
System.out.println("rest = " + old);
i = old.indexOf(frag);
System.out.println("i = "+ i);
}
return old;
}
Here the index of first occurrence is obtained outside the “while loop” and if this loop runs until index value is >-1. It extracts the rest of the characters other than “frag” from the index and all the characters for which the given set of characters are removed.
Answer:
A hot spot
Explanation:
Q:
The range of an area where users can access the Internet via high frequency radio signals transmitting an Internet signal from a wireless router is known as a _____. A) HotspotB) PAN…
A:
A) hotspot Bluetooth is for short distance and pan is Personal area networks (PANs) connect an individual's personal devices
Answer:
Check the explanation
Explanation:
1.
System = 256Byte = 8 bit
Cache = 64B , block size = 16 byte.
A) Direct Mapped Cache:
Block offset = log (Block size) = log 16 = 4bit
Total # of block inside cache = 4.
Therefore index offset = log 4 = 2bit.
Remaining is tag bits.
Therefore tag bits = 8-(4+2) = 8-6 = 2 bits
Tag Index offset Block offset
(2 bits) (2 bits) (4 bits)
Fully associative cache :
In fully associative cache, any of main memory block can be placed anywhere in cache. Therefore index offset =0 bits.
Therefore tag bits = 8-block offset bit= 8-4 =4bits
Tag Block offset
(4 bits) (4 bits)
It’s RFID because they didn’t have enough money
Answer: D. enter each major point from the outline on a separate line
